RST.9-10.9Common CoreELALiteracy in Science and Technical SubjectsGrades 9-10
RST.9-10.9: Comparing a Text's Findings With Other Sources and Your Own Experiment
In plain English: RST.9-10.9 is the Common Core ELA standard that asks students in grades 9-10 to compare and contrast the findings in a science text with those from other sources, including their own experiments, and to say when the findings support or contradict earlier explanations or accounts. It is usually taught in chemistry, biology and physical science courses.
Compare and contrast findings presented in a text to those from other sources (including their own experiments), noting when the findings support or contradict previous explanations or accounts.
Common Core State Standards for English Language Arts & Literacy · Domain: Reading Standards for Literacy in Science and Technical Subjects 6-12 · Cluster: Integration of Knowledge and Ideas · Official standard
A science text reports findings: what was measured or observed, and what the author concluded. RST.9-10.9 asks students to set those findings beside findings from other sources, including experiments they run themselves, to say where the sources agree and where they differ, and to decide whether the findings support or contradict an earlier explanation or account. This lesson teaches a four-step routine: state each finding with its number and conditions, line the findings up on the same question, compare and contrast them, and then label each earlier explanation as supported, contradicted or not tested.
The question for the whole lesson is an old one: what is air made of, and how much of it is the part we breathe? Students read Antoine Lavoisier's account of his twelve-day mercury experiment (1789, in Robert Kerr's 1790 translation), William Ramsay's account of Henry Cavendish's analyses of air (1896), and a lab report of a steel-wool experiment that the class runs itself. A modern table of the composition of dry air gives the present-day values. The sample class data on this page are invented; classes that run the experiment use their own results.
Learning Objectives
By the end of this lesson, students will be able to:
State a finding from a science text precisely, with its number, its units and the conditions of measurement
Compare and contrast a text's findings with those of another text, a data table and their own experiment
Explain a difference between findings by pointing to a difference in method
Decide whether a set of findings supports, contradicts or does not test an earlier explanation or account, and word the judgment to match the evidence
Prior Knowledge Required
Students should already be comfortable with:
Comparing information from an experiment with information from a text on the same topic RST.6-8.9
Citing specific textual evidence from a science text, attending to precise details RST.9-10.1
Remind students of the tubes they set up two or three days ago in Activity 1, and show the modern table below. Tell them that people argued for centuries about what air is: Aristotle counted it as one of four elements, and in the 1700s many chemists explained burning with the phlogiston theory, which held that a burning substance gives off a substance called phlogiston into the air.
Modern composition of dry air at sea level, percent by volume (standard reference values)
Gas
Percent of dry air
Nitrogen
78.08
Oxygen
20.95
Argon
0.93
Carbon dioxide
about 0.04 (about 420 parts per million in 2024)
Neon, helium and other gases
less than 0.01 in all
Warm-Up Prompt
If this table is right, what share of the air in your test tube should the rusting steel wool be able to use up, and what share should be left? What would it mean if your tube showed a very different number?
Take answers. If rusting uses only oxygen, about a fifth of the air should go and about four fifths should stay. A very different result could mean the table is wrong, or, far more likely, that something in the experiment went differently. Say that this is today's skill: RST.9-10.9 asks them to compare and contrast findings in a text with those from other sources, including their own experiments, and to note when the findings support or contradict earlier explanations or accounts.
Direct Instruction15-20 minutes
The routine. Post the four steps and keep them up. (1) State each finding as one sentence with its number, units and conditions. (2) Line up the findings on the same question; two findings can only be compared if they answer the same question. (3) Compare and contrast: say where the findings agree, where they differ and by how much, and look for a difference in method that could explain the gap. (4) Judge the earlier explanation or account: supported, contradicted or not tested, and how strongly. A finding supports an explanation when the explanation predicts it; it contradicts an explanation when the explanation predicts something else.
Model with Lavoisier (T1). Antoine Lavoisier (1743-1794) was a French chemist whose experiments on burning and on the air helped to overturn the phlogiston theory. Show Diagram 1 and walk through his apparatus before reading: mercury is heated in a flask whose bent neck leads into a bell-shaped glass standing in a trough of mercury, so a fixed sample of air is trapped above the hot metal. Read T1 aloud. Mercury is toxic, and its vapor is dangerous to breathe: this experiment is shown only as a historical account and is never repeated in class.
1I took a matrass (A, fig. 14. plate II.) of about 36 cubical inches capacity, having a long neck B C D E, of six or seven lines internal diameter, and having bent the neck as in Plate IV. Fig. 2. so as to allow of its being placed in the furnace M M N N, in such a manner that the extremity of its neck E might be inserted under a bell-glass F G, placed in a trough of quicksilver R R S S; I introduced four ounces of pure mercury into the matrass, and, by means of a syphon, exhausted the air in the receiver F G, so as to raise the quicksilver to L L, and I carefully marked the height at which it stood by pasting on a slip of paper. Having accurately noted the height of the thermometer and barometer, I lighted a fire in the furnace M M N N, which I kept up almost continually during twelve days, so as to keep the quicksilver always almost at its boiling point. Nothing remarkable took place during the first day: The Mercury, though not boiling, was continually evaporating, and covered the interior surface of the vessels with small drops, at first very minute, which gradually augmenting to a sufficient size, fell back into the mass at the bottom of the vessel. On the second day, small red particles began to appear on the surface of the mercury, which, during the four or five following days, gradually increased in size and number; after which they ceased to increase in either respect. At the end of twelve days, seeing that the calcination of the mercury did not at all increase, I extinguished the fire, and allowed the vessels to cool. The bulk of air in the body and neck of the matrass, and in the bell-glass, reduced to a medium of 28 inches of the barometer and 10 deg. (54.5 deg.) of the thermometer, at the commencement of the experiment was about 50 cubical inches. At the end of the experiment the remaining air, reduced to the same medium pressure and temperature, was only between 42 and 43 cubical inches; consequently it had lost about 1/6 of its bulk. Afterwards, having collected all the red particles, formed during the experiment, from the running mercury in which they floated, I found these to amount to 45 grains.
2I was obliged to repeat this experiment several times, as it is difficult in one experiment both to preserve the whole air upon which we operate, and to collect the whole of the red particles, or calx of mercury, which is formed during the calcination. It will often happen in the sequel, that I shall, in this manner, give in one detail the results of two or three experiments of the same nature.
3The air which remained after the calcination of the mercury in this experiment, and which was reduced to 5/6 of its former bulk, was no longer fit either for respiration or for combustion; animals being introduced into it were suffocated in a few seconds, and when a taper was plunged into it, it was extinguished as if it had been immersed into water.
Antoine Lavoisier, translated by Robert Kerr, Elements of Chemistry (Part I, chapter III: Lavoisier's twelve-day mercury experiment; excerpt) (1789; this edition 1790). Public domain (published 1790). Source text.
Pulling out the finding (T1, paragraph 1)
Lavoisier's first paragraph is mostly about equipment. What exactly did he find, and under what conditions did he measure it?
Result: The finding is in the last sentences: the trapped air was "about 50 cubical inches" at the start and "only between 42 and 43 cubical inches" at the end, so it "had lost about 1/6 of its bulk," and 45 grains of red particles had formed. The condition that makes the numbers comparable is also stated: both volumes were "reduced to a medium of 28 inches of the barometer and 10 deg." of the thermometer, that is, corrected to the same pressure and temperature. Before comparing a finding with anything else, students write it as one sentence with its number and its conditions.
Comparing with a modern source (T1 and the modern table)
Compare Lavoisier's finding with the modern composition of dry air. What do the two sources agree on, and where do they differ?
Result: Compare: both sources show that only part of the air can be used up and that the rest will not keep a flame or an animal alive. Lavoisier's leftover air put out a taper "as if it had been immersed into water"; the modern table shows that the leftover is almost all nitrogen and argon, gases that do not support burning. Contrast: "about 1/6" is 100 ÷ 6 ≈ 16.7 percent, and 7 to 8 cubic inches out of 50 is 14 to 16 percent, while the modern oxygen share is 20.95 percent. Lavoisier's number is 4 to 7 percentage points low. Why it is low is a question to hold: T4 gives Lavoisier's own answer.
Close the model by naming what students just did. They stated the finding with its conditions (step 1), lined it up with the modern table on the same question, "what share of the air can be used up?" (step 2), and compared and contrasted it (step 3). Step 4 comes next, with a second text.
Guided Practice15-20 minutes
Pairs read Ramsay's account of Henry Cavendish (T2). Cavendish (1731-1810) was an English chemist and physicist; Ramsay (1852-1916) was a chemist who, with Lord Rayleigh, found argon in the air in 1894. Ramsay uses the phlogiston theory's names: "dephlogisticated air" is oxygen and "phlogisticated air" is nitrogen. Nitric oxide is a gas that combines with oxygen and dissolves in water, so it can remove the oxygen from a sample.
1It was in 1777 that he commenced his beautiful “Experiments on Air,” the first account of which was published in 1783. They led to the discovery of the constant quantitative composition of the atmosphere, of the compound nature of water, and of the composition of nitric acid, and pointed the way to the recent discovery of argon.
2In determining the composition of the atmosphere, Cavendish made use of nitric oxide in presence of water, as a means of removing oxygen. This process, originally devised by Mayow, was rediscovered by Priestley, who employed it to ascertain the “goodness” of various samples of air; in Cavendish’s hands it became an accurate quantitative method. The title of his paper, published in the Philosophical Transactions for 1783, is “Of a new Eudiometer.” The term “eudiometer,” signifying “measurer of goodness,” was devised when it was supposed that ordinary air presented considerable variations in its power of supporting respiration and combustion, according to the seasons, and according to the place from which it was collected. Dr. Ingenhousz had found a greater absorption when air from near the sea-coast was tested by Priestley’s method with nitric oxide, than when town-air was employed; and he ascribed the salubrious nature of sea-air to its being richer in “vital air.” The Abbé Fontana, too, had made similar experiments, and had come to similar conclusions. Cavendish modified Fontana’s apparatus, rendering it capable of giving more accurate results; and during the last half of the year 1781 he analysed the air collected on sixty days, some fine, some wet, and some foggy. He also collected air from different localities, sometimes at Marlborough Street, sometimes at Kensington, which was then a country village. The results of his analyses establish as the composition of air, freed from carbon dioxide by potash:
379·16 per cent of phlogisticated air (nitrogen). 20·84 per cent of dephlogisticated air (oxygen).
4This result does not differ materially from those obtained by the best modern analyses, which give, within very small variations:
579·04 per cent of nitrogen and argon, 20·96 per cent of oxygen,
6after absorption of carbon dioxide, ammonia, and water-vapour.
William Ramsay, The Gases of the Atmosphere (chapter on Cavendish: his analyses of air in 1781; excerpt) (1896). Public domain (published 1896). Source text.
Then groups read their own tubes from Activity 1 (Part 2, the reading) and add their numbers to a class table. Classes that could not run the experiment use the sample data sheet below, T3. Diagram 2 has an empty bar for the class result.
1Question. When iron rusts in a closed pocket of air, how much of that air is used up? We tested this in class, two days after reading about Lavoisier's mercury experiment. The class and the data are invented for teaching; the method is a standard classroom one.
2Method. Each of six groups pulled apart a 1 g pad of fine steel wool, soaked it in white vinegar for one minute to remove its oily coating, shook it, and pushed it to the closed end of a 20 cm test tube. We turned the tube upside down in a tall beaker of water, lowered it until about 5 cm of water stood inside, and clamped it. With a ruler we measured the air column, from the closed end to the water surface inside the tube. Before every reading we moved the tube up or down until the water inside and outside were at the same level, so that the trapped air was at room pressure. The room stayed at 21 °C for every reading.
3Results. The length of the air column in each tube was: Group 1: 152 mm at the start, 123 mm after 3 days. Group 2: 148 mm at the start, 119 mm after 3 days. Group 3: 150 mm at the start, 121 mm after 3 days. Group 4: 155 mm at the start, 124 mm after 3 days. Group 5: 149 mm at the start, 136 mm after 3 days. Group 6: 151 mm at the start, 121 mm after 3 days.
4Notes. Group 5 forgot to soak its steel wool in vinegar. Groups 1, 2 and 3 also read their tubes after 24 hours: 152 mm to 128 mm, 148 mm to 125 mm, and 150 mm to 126 mm. In every group except Group 5, the water level did not move between day 2 and day 3. The steel wool had turned orange-brown with rust.
5Our conclusion. About one fifth of the air was used up by the rusting iron, and the air left in the tubes put out a burning splint when our teacher tested one tube. So air is about 20 percent oxygen, and Lavoisier was wrong.
Written for this page (the class and its data are invented), Lab Report: How Much of the Air Does Rusting Steel Wool Use Up? (class data sheet, invented data). Original passage written for this page.
The results in T3 as a table (invented data): length of the air column in mm
Group
At the start
After 24 hours
After 3 days
1
152
128
123
2
148
125
119
3
150
126
121
4
155
not read
124
5
149
not read
136
6
151
not read
121
A finding that contradicts an earlier account (T2)
According to Ramsay, what did Ingenhousz and Fontana report about the air, and how do Cavendish's findings bear on their account?
Result: The earlier account: Ingenhousz "had found a greater absorption" in sea-coast air than in town air and "ascribed the salubrious nature of sea-air to its being richer in 'vital air'"; Fontana came "to similar conclusions." Cavendish tested air "collected on sixty days, some fine, some wet, and some foggy," from a London street and from Kensington, with a more accurate instrument, and found one composition: 20.84 percent oxygen. His findings contradict the account that the share of oxygen changes from place to place or day to day. They do not test sea air directly, so the fairest wording is that they cast strong doubt on it.
Comparing your own experiment (T3, Group 1)
Group 1's air column went from 152 mm to 123 mm. What share of the air was used up, and how does the method compare with Lavoisier's?
Result: The tube has the same width all the way along, so the volume of air is proportional to the length of the column. Group 1 lost 152 - 123 = 29 mm, and 29 ÷ 152 ≈ 0.191, or about 19.1 percent. Compare the methods: both trap air over a liquid, let a metal take up part of it, and measure how much the trapped air shrinks. Contrast: Lavoisier heated mercury almost to boiling for twelve days, while the class let iron rust at 21 °C for three days, and the class corrected for pressure by leveling the water, while Lavoisier corrected his readings to a standard barometer and thermometer.
Debrief with step 4: Does the class experiment support or contradict the phlogiston theory's claim that burning and rusting add something to the air? The air shrank instead of gaining anything, so the result fits Lavoisier's view that the metal takes something out of the air. Push students to word this carefully: one experiment contradicts the prediction, but a supporter of the theory in 1780 had ways to explain it away, which is why Lavoisier did more than measure the air (T4).
Independent Practice20 minutes
Students read T4, the four paragraphs that follow T1 in Lavoisier's chapter, and answer quiz questions 1-20. Questions 1-6 and 15-17 use T4; questions 7-10 and 18 use the lab report T3; question 11 uses Diagram 2; questions 12 and 13 use T1; question 14 uses T2; and questions 19 and 20 use several sources together. Gloss before reading: a "retort" is a glass vessel with a long bent neck used for heating substances, a "taper" is a thin candle, and "elastic fluid" means gas.
1In the next place, I took the 45 grains of red matter formed during this experiment, which I put into a small glass retort, having a proper apparatus for receiving such liquid, or gasseous product, as might be extracted: Having applied a fire to the retort in a furnace, I observed that, in proportion as the red matter became heated, the intensity of its colour augmented. When the retort was almost red hot, the red matter began gradually to decrease in bulk, and in a few minutes after it disappeared altogether; at the same time 41-1/2 grains of running mercury were collected in the recipient, and 7 or 8 cubical inches of elastic fluid, greatly more capable of supporting both respiration and combustion than atmospherical air, were collected in the bell-glass.
2A part of this air being put into a glass tube of about an inch diameter, showed the following properties: A taper burned in it with a dazzling splendour, and charcoal, instead of consuming quietly as it does in common air, burnt with a flame, attended with a decrepitating noise, like phosphorus, and threw out such a brilliant light that the eyes could hardly endure it. This species of air was discovered almost at the same time by Mr Priestley, Mr Scheele, and myself. Mr Priestley gave it the name of dephlogisticated air, Mr Scheele called it empyreal air. At first I named it highly respirable air, to which has since been substituted the term of vital air. We shall presently see what we ought to think of these denominations.
3In reflecting upon the circumstances of this experiment, we readily perceive, that the mercury, during its calcination, absorbs the salubrious and respirable part of the air, or, to speak more strictly, the base of this respirable part; that the remaining air is a species of mephitis, incapable of supporting combustion or respiration; and consequently that atmospheric air is composed of two elastic fluids of different and opposite qualities. As a proof of this important truth, if we recombine these two elastic fluids, which we have separately obtained in the above experiment, viz. the 42 cubical inches of mephitis, with the 8 cubical inches of respirable air, we reproduce an air precisely similar to that of the atmosphere, and possessing nearly the same power of supporting combustion and respiration, and of contributing to the calcination of metals.
4Although this experiment furnishes us with a very simple means of obtaining the two principal elastic fluids which compose our atmosphere, separate from each other, yet it does not give us an exact idea of the proportion in which these two enter into its composition: For the attraction of mercury to the respirable part of the air, or rather to its base, is not sufficiently strong to overcome all the circumstances which oppose this union. These obstacles are the mutual adhesion of the two constituent parts of the atmosphere for each other, and the elective attraction which unites the base of vital air with caloric; in consequence of these, when the calcination ends, or is at least carried as far as is possible, in a determinate quantity of atmospheric air, there still remains a portion of respirable air united to the mephitis, which the mercury cannot separate. I shall afterwards show, that, at least in our climate, the atmospheric air is composed of respirable and mephitic airs, in the proportion of 27 and 73; and I shall then discuss the causes of the uncertainty which still exists with respect to the exactness of that proportion.
Antoine Lavoisier, translated by Robert Kerr, Elements of Chemistry (Part I, chapter III: what Lavoisier concluded from the mercury experiment; excerpt) (1789; this edition 1790). Public domain (published 1790). Source text.
Closure5 minutes
Exit ticket: "Write one sentence comparing your class result with one finding from a text, and one sentence saying which earlier explanation or account your result supports or contradicts, and how strongly." Sort the tickets into "comparison with a number and a judgment," "comparison without a judgment" and "judgment without a comparison" to plan the next lesson.
Teacher note on the historical texts. Lavoisier and Ramsay write in the language of their time. "Animals being introduced into it were suffocated" in T1 describes animal experiments that were routine in eighteenth-century chemistry; discuss them as part of the history, and let students who find them upsetting focus on the measurements. Words such as "salubrious" (healthy), "mephitis" (unbreathable air) and "caloric" (heat, then thought to be a substance) are period vocabulary. The texts contain no slurs. Lavoisier's view that oxygen combines with metals and fuels when they burn is the modern view; his "caloric" and his figure of 27 percent were later abandoned. Mercury and its red calx are toxic: they appear on this page as data only.
Homework passage. The homework uses a later part of Ramsay's book, below: Lord Rayleigh's measurements of the densities of air, oxygen and nitrogen, published in 1893, and a puzzle they raised.
1Up to within the last few years it was supposed that the constituents of air had all been discovered. But Lord Rayleigh and Professor William Ramsay have recently found that the supposed nitrogen of the air is in reality a mixture of nitrogen with a new gaseous element, to which they have given the name “argon,” on account of its chemical inactivity (ἂργον, idle, inactive).
2[...] He found the weights of one litre of oxygen, nitrogen, and air to be
3Oxygen 1·42952 grams “Nitrogen” 1·25718 " Air 1·29327 "
4A simple calculation leads to the composition of purified air. The percentage of oxygen must be 20·941, and that of “nitrogen” 79·059, in order to give a mixture of which the weight of a litre is 1·29327. Now, this corresponds with the results of the best analyses, quoted above. And the accuracy of these determinations of density is confirmed by this means, as well as by results of other experiments made by Leduc, von Jolly, and Morley.
[...]
5It was next deemed necessary to test whether nitrogen was homogeneous by preparing it too by several different methods. In the same paper Lord Rayleigh (p. 146) mentions that nitrogen, prepared from ammonia, its compound with hydrogen, is somewhat lighter than “atmospheric nitrogen,” the deficiency in weight amounting to about 1 part in 200. Now it is evident from inspection of the numbers quoted above, that the accuracy of the density determination may be trusted to within 1 part in 10,000, and that the balance would detect a discrepancy one-fiftieth of that observed in the densities of “atmospheric” and “chemical” nitrogen. In a letter to Nature, Lord Rayleigh asked for suggestions from chemists as to the reason of this curious anomaly, but his letter went without reply. [...]
William Ramsay, The Gases of the Atmosphere (chapter on argon: Lord Rayleigh's densities of air and nitrogen; excerpt, cuts marked [...]) (1896). Public domain (published 1896). Source text.
Differentiation Strategies
For Struggling Students
Give a comparison chart with four columns (Source / Finding with number / Method / Agrees or differs with) and fill in the Lavoisier row together
Provide sentence frames: "Both ____ and ____ found ____. They differ because ____, probably because ____." and "This finding supports / contradicts ____'s account that ____."
Pre-teach the historical vocabulary with a glossary card: matrass, quicksilver, calx, mephitis, dephlogisticated air, eudiometer
For Advanced Students
Read the rest of Lavoisier's chapter III in the full text, where he burns iron in the respirable air, and compare the share of gas used up there with his mercury result in T1
Research Cavendish's small unabsorbed bubble of "phlogisticated air" (1785) and explain how it was later linked to argon
Design a change to the steel-wool test that would tell whether the leftover gas is a single substance, and say what result would contradict that idea
Assessment Guidance
What to Look For
Strong answers state each finding with its number and conditions, compare findings only when they answer the same question, name both a likeness and a difference, and explain a difference by a difference in method before calling a source wrong. Strong judgments say which earlier explanation or account is supported or contradicted and word the strength to match the evidence. Watch for students who compare numbers measured under different conditions, who treat any difference as proof that a source is wrong, who ignore their own group's errors, and who say a finding "proves" a theory.
02
Classroom Activities
3 Activities
1
The Steel Wool Test
15 min set-up, 10 min reading 2-3 days laterGroups of 3
This is the class's own experiment, the source that RST.9-10.9 names directly. Groups trap air over water with damp steel wool and measure how much of the air the rusting iron uses up. Set it up two or three days before the lesson; the reading happens in Guided Practice. The method is the one in T3.
Part 1: Set-Up (15 min)
Goggles and gloves on. Steel wool splinters can cut skin and get into eyes.
Pull apart a 1 g pad of fine steel wool, soak it in white vinegar for one minute to remove its oily coating, and shake it.
Push it to the closed end of a 20 cm test tube so it stays put when the tube is turned over.
Turn the tube upside down in a tall 1 L beaker of water, lower it until about 5 cm of water stands inside, and clamp it.
Move the tube until the water inside and outside are level, then measure the air column in mm from the closed end to the water surface inside. Record it with the room temperature.
Set up one extra tube with dry, unsoaked steel wool, and one with no steel wool at all, as class controls.
Part 2: Reading (10 min)
Check that the room temperature is within 1 °C of the set-up temperature.
Level the water inside and outside the tube, then measure the air column again.
Compute the percent of the air used up: (start - end) ÷ start × 100.
Add your result to the class table and to the empty bar in Diagram 2.
Teacher Key
After three days, well-soaked tubes usually show about 18-21 percent of the air used up; the result cannot honestly exceed about 21 percent, because only oxygen is taken up.
Low results usually come from steel wool that was not soaked (its coating slows rusting), from reading before the rusting has finished, or from not leveling the water.
The tube with no steel wool should show almost no change; a change there measures the error from temperature and pressure, since 1 °C changes a gas volume by about 0.3 percent.
The rounded end of a test tube holds slightly less than a straight tube of the same length, so the percentages are close but not exact.
Discussion Questions
Why must the water be leveled before every reading?
What does the tube with no steel wool tell you that the other tubes cannot?
Your group's result is 2 percentage points below another group's. What would you check before deciding which one is closer to the truth?
2
Support or Contradict? Card Match
15 minPairs
Pairs get four explanation cards (earlier explanations or accounts) and ten finding cards drawn from T1, T2, T3 and the modern table. For each finding, they choose the explanation it bears on, place it on the Supports or Contradicts side of that card, or set it aside as Not tested, and write the words from the source that decided it.
The 4 Explanation Cards
Air is a single element (Aristotle's four elements).
When a metal is heated in air, it gives off phlogiston into the air (phlogiston theory).
Sea air is healthier because it holds more "vital air" than town air (Ingenhousz, as reported in T2).
The air is about one fifth oxygen everywhere at ground level (modern account).
The 10 Finding Cards
Lavoisier's trapped air shrank from about 50 to 42-43 cubic inches while mercury was heated in it (T1).
The air left after Lavoisier's experiment put out a taper (T1).
Cavendish's analyses on sixty days in 1781, fine, wet and foggy, all gave 20.84 percent oxygen (T2).
Cavendish's samples came from a London street and from Kensington, then a village (T2).
In T3, five of the six groups found that about one fifth of the air in their tubes was used up.
In Activity 1, the control tube with no steel wool showed almost no change in its air column.
The modern table gives 20.95 percent oxygen in dry air.
Ramsay reports modern analyses of 20.96 percent oxygen (T2).
Lavoisier's experiment ran for twelve days and was repeated several times (T1).
Steel wool in T3 turned orange-brown with rust.
Teacher Key
Card 1: contradicts A (part of the air is taken up and part is not) and contradicts B's simple prediction (the air shrank, while the theory says something is added to it).
Card 2: contradicts A: the leftover air behaves differently from the whole.
Card 3: contradicts C and supports D: the share did not change with the weather.
Card 4: bears on C only weakly: Kensington is not the sea coast, so C is not directly tested.
Card 5: supports D, and contradicts B for rusting.
Card 6: not tested for any card: it checks the method (temperature and pressure), not a property of air.
Cards 7 and 8: support D.
Card 9: not tested: it describes the method and helps judge Card 1.
Card 10: not tested on its own; it shows that a new substance formed, which B and D would both allow.
Discussion Questions
Card 4 seems to contradict explanation C. Why is "not directly tested" the fairer label?
Which single card is the strongest evidence against explanation B, and why?
Is any explanation supported by every source on the page? What does that agreement add?
3
Our Result Beside the Record
15 minGroups of 3
Groups write a three-sentence comparison statement that places the class result beside the findings of Lavoisier and Cavendish, using a frame, then trade statements with another group, which checks every number against its source and underlines the one word that states the judgment (supports, contradicts, not tested).
The Frame
"Our class found that ____ percent of the trapped air was used up by rusting iron in ____ days (our data)."
"This is close to / different from ____'s finding of ____, and the difference is probably due to ____."
"Together, these findings support / contradict ____'s account that ____, because ____."
Teacher Key
Sentence 1 needs the number, the method and the time; a class mean needs the number of groups it averages and any group left out, with the reason.
Sentence 2 is strong when it names a difference in method: heating for twelve days against rusting at room temperature, nitric oxide against iron, or one reading against many.
Sentence 3 is strong when the judgment is as strong as the evidence and no stronger: "support" or "contradict," not "prove" or "disprove."
Discussion Questions
Should a class result ever outweigh a published finding? What would you need to believe that it does?
Which source would you trust most on the share of oxygen in the air, and why?
Variation: Two Classes
Where two classes ran the test, give each group the other class's mean and ask for a fourth sentence: whether the two class results agree with each other, and what that adds to the comparison.
03
Diagrams & Visual Aids
2 diagrams
Diagram 1: Lavoisier's Mercury Experiment and the Class Steel-Wool Test Side by Side
A schematic, not to scale. Left: in T1, Lavoisier heats mercury in a long-necked flask for twelve days; the neck opens into a bell-glass standing in a trough of mercury, so a fixed sample of air is trapped, and he marks its level. Right: in the class test (T3 and Activity 1), damp steel wool rusts at the closed end of an upside-down test tube standing in water, and the air column is measured with a ruler. Both methods let a metal take up part of a trapped sample of air.
Diagram 2: The Share of Oxygen in Air, Source by Source, Drawn to Scale
Four findings from this page, drawn to scale from zero: Lavoisier's mercury result ("about 1/6," T1), the proportion Lavoisier states for the respirable part of the air (27 of 100, T4), Cavendish's 1781 analyses (20.84 percent, T2) and the modern value for dry air (20.95 percent, from the Warm-Up table). The dashed frame is where students draw the class steel-wool result.
04
Homework Assignment
~30 min
RST.9-10.9 Homework: Rayleigh's Densities and the Puzzle of Nitrogen
Directions: Use Ramsay's account of Lord Rayleigh's measurements (T5), printed at the end of the Closure phase of the lesson plan, together with T1, T2, T3 and T4. Paragraphs are numbered. Lord Rayleigh (1842-1919) was an English physicist; a "litre" is a liter, and the density of a gas is the mass of one liter of it. Quote the words you use and show your arithmetic.
Part 1: Comparing Rayleigh's Findings (Problems 1-3)
In T5, paragraph 4, Ramsay says a "simple calculation" from the three densities gives 20.941 percent oxygen. (a) Check it: compute the mass of one liter of a mixture that is 20.941 percent oxygen and 79.059 percent "nitrogen" by volume, using the densities in paragraph 3, and compare it with the density of air. (b) Rayleigh weighed gases; Cavendish (T2) used up the oxygen with nitric oxide. Explain why it matters that two such different methods agree.
Compare Rayleigh's finding of 20.941 percent oxygen (T5) with Lavoisier's stated proportion of 27 (T4) and with Cavendish's 20.84 percent (T2). Give each difference in percentage points, and say which of the two earlier findings Rayleigh's supports and which it contradicts.
T5, paragraph 5, reports that nitrogen made from ammonia was lighter than "atmospheric nitrogen" by "about 1 part in 200." (a) Why does Ramsay point out that the density could be trusted "to within 1 part in 10,000"? (b) What earlier account of the air does this finding contradict? Use T4, paragraph 3, or T2.
Part 2: Your Experiment and Rayleigh's (Problems 4-5)
Paragraph 1 of T5 says the supposed nitrogen of the air is really a mixture of nitrogen and a new gas, argon. Could the steel-wool test in T3 or Activity 1 have detected argon? Explain what rusting does and does not remove from the trapped air, and say what the test's leftover gas really is.
Your class result and Rayleigh's both answer the question "what share of the air is oxygen?" Write two sentences comparing them: one on how close the numbers are, and one on why a single class result cannot confirm Rayleigh's third decimal place.
Part 3: Writing the Comparison (Problem 6)
Write a paragraph of 6-8 sentences that answers the question "What is air made of?" by comparing the findings of Lavoisier (T1 and T4), Cavendish (T2), Rayleigh (T5) and your class (T3 or your own data). Say where they agree, where they differ and why, and name one earlier explanation or account that the findings contradict and one that they support.
Rubric
Criterion
Full Credit (2 pts)
Partial Credit (1 pt)
No Credit (0 pts)
Findings Stated
States each finding accurately, with its number and source
States findings loosely or without numbers
Misstates the findings
Compare and Contrast
Names likenesses and differences and gives the size of each difference
Names only likenesses or only differences
Lists findings without comparing them
Method Explained
Explains a difference in results by a difference in method
Mentions method without linking it to the results
Calls a source wrong without considering method
Support or Contradiction
Names the earlier explanation or account and words the judgment to match the evidence
Gives a judgment that is too strong or too vague
Gives no judgment
05
Quiz: 20 Questions
Interactive, with answers
Instructions
Questions 1-6 and 15-17 use Lavoisier's conclusions (T4), in the Independent Practice phase of the lesson plan, and questions 7-10 and 18 use the lab report (T3) in Guided Practice. Question 11 uses Diagram 2, questions 12 and 13 use T1 in Direct Instruction, question 14 uses Ramsay's account of Cavendish (T2), and questions 19 and 20 use several sources (paragraphs are numbered). Show your arithmetic and quote the words you rely on in the short answers. Your score updates as you answer, and Reset quiz clears everything so you or your students can try again.
Multiple choice: pick an option to check it. Short answer: write your answer, then reveal the model answer.
0 of 20 answered · 0 correct
Question 1 of 20 · Multiple Choice
In T4, paragraph 1, Lavoisier heats the 45 grains of red matter and collects 41 1/2 grains of mercury and 7 or 8 cubic inches of gas. The phlogiston theory held that a metal is its calx plus phlogiston, so a calx should weigh less than the metal it comes from. Which finding contradicts that account?
Answer: B
The calx weighed 45 grains and gave back only 41 1/2 grains of mercury, so the calx was heavier than the metal in it. If a calx were metal minus phlogiston, it would weigh less than the metal, not more; the extra weight is the gas that came off. Choice A describes a color change that neither account predicts. Choice C is true but tells nothing about weight. Choice D shows that a gas came off, which the phlogiston theory could also describe; only the weights set the two accounts against each other.
Question 2 of 20 · Multiple Choice
In T4, paragraph 2, Lavoisier lists the names Priestley and Scheele gave the new gas and adds, "We shall presently see what we ought to think of these denominations." What is the main point of the paragraph for a reader comparing sources?
Answer: C
The paragraph says the gas "was discovered almost at the same time by Mr Priestley, Mr Scheele, and myself," so the finding is shared. The names differ: "dephlogisticated air" comes from the phlogiston theory, and "We shall presently see what we ought to think of these denominations" signals that Lavoisier will question the explanation built into them. Choice A misreads "almost at the same time" as "first." Choice B contradicts the paragraph, which calls it one "species of air." Choice D is not claimed; Lavoisier's names describe what the gas does ("highly respirable," "vital"), not how it was made.
Question 3 of 20 · Multiple Choice
In T4, paragraph 3, what does Lavoisier offer as proof that atmospheric air is made of two different gases?
Answer: A
Lavoisier writes that "if we recombine these two elastic fluids," the 42 cubic inches of mephitis and the 8 of respirable air, "we reproduce an air precisely similar to that of the atmosphere." Taking air apart is analysis; putting it back together is synthesis, and here he offers both. Choice B is from T1 and describes the calx forming, not a proof of two gases. Choice C is a condition of the measurement, not a proof. Choice D is not in the paragraph; T4 names Priestley and Scheele only as finders of the gas.
Question 4 of 20 · Multiple Choice
In T4, paragraph 4, Lavoisier states that atmospheric air is made of respirable and mephitic airs "in the proportion of 27 and 73." How does this compare with Cavendish's finding in T2?
Answer: D
Cavendish found 20.84 percent oxygen; Lavoisier states 27 percent, and 27 - 20.84 = 6.16, about 6 percentage points higher. The two sources agree that air has a respirable and an unbreathable part and contrast on how much of each. Choice A ignores the gap. Choice B compares Lavoisier's 73 for the mephitic part with Cavendish's 20.84 for oxygen, mixing up the two parts (73 - 20.84 ≈ 52). Choice C has the direction backward.
Question 5 of 20 · Multiple Choice
Lavoisier's own experiment in T1 used up only about 1/6 of the air, yet in T4 he gives 27 parts in 100 for the respirable part. How does T4, paragraph 4, explain why the experiment took up less?
Answer: B
Paragraph 4 says "the attraction of mercury to the respirable part of the air, or rather to its base, is not sufficiently strong to overcome all the circumstances which oppose this union," so "there still remains a portion of respirable air united to the mephitis, which the mercury cannot separate." Choice A is a reasonable worry, but T1 says the difficulty was keeping the air and collecting the calx, and T4 does not blame leaks. Choice C is ruled out by T1: the volumes were "reduced to the same medium pressure and temperature." Choice D is not in the text: T4 never says the bell-glass was too small.
Question 6 of 20 · Multiple Choice
Suppose Lavoisier's figure of 27 parts in 100 were correct. About how many cubic inches of respirable air should his 50 cubic inches of air in T1 have held?
Answer: D
27 percent of 50 is 0.27 × 50 = 13.5 cubic inches, far more than the 7 or 8 cubic inches his experiment took up and got back. Choice A uses the 73 parts of mephitis instead of the 27 (0.73 × 50 = 36.5). Choice B uses the 1/6 from T1 (50 ÷ 6 ≈ 8.3), which is what he measured, not what 27 percent predicts. Choice C subtracts 27 from 50, treating a percentage as a volume.
Question 7 of 20 · Multiple Choice
In the lab report (T3), which group's result should be set aside before the class compares its findings with Lavoisier's and Cavendish's, and why?
Answer: C
The notes say "Group 5 forgot to soak its steel wool in vinegar," which leaves the oily coating that slows rusting, and its air column shrank far less than any other group's (149 mm to 136 mm). A result from a flawed run is set aside with the reason stated, not averaged in. Choice A: a longer column changes the volume, not the percentage. Choice B: extra readings are a strength. Choice D would throw out a result because it agrees with another source, which is the opposite of a fair comparison.
Question 8 of 20 · Multiple Choice
Group 4's air column in T3 went from 155 mm to 124 mm. What percent of the air was used up?
Answer: B
The column lost 155 - 124 = 31 mm, and 31 ÷ 155 = 0.20, or 20.0 percent of the air. Because the tube is the same width all the way along, lengths stand for volumes. Choice A divides by the final length instead of the starting length (31 ÷ 124 = 0.25). Choice C gives the share of air left, 124 ÷ 155. Choice D treats the 31 mm as a percentage.
Question 9 of 20 · Multiple Choice
In T3, Groups 1-3 read their tubes after 24 hours as well. A student notices that their 24-hour results, about 15-16 percent, are close to Lavoisier's "about 1/6" and says, "So the 24-hour readings support Lavoisier's number." What is the best reply?
Answer: A
The report says the water level stopped moving only "between day 2 and day 3," so at 24 hours the iron was still taking oxygen out of the air; the 3-day readings for the same groups are higher. Two unfinished processes can land on similar numbers for different reasons, so the match is not support. Choice B treats closeness of numbers as agreement without checking what each number measures. Choice C confuses the length of an experiment with its result. Choice D goes too far: the readings can be compared, but only as unfinished results.
Question 10 of 20 · Multiple Choice
Leaving out Group 5, what is the mean of the percentages of air used up by the other five groups in T3?
Answer: A
Work out each group's percentage as in question 8, for Groups 1, 2, 3, 4 and 6; the five percentages add to about 97.9, and 97.9 ÷ 5 ≈ 19.6 percent, a little below Cavendish's 20.84 and the modern 20.95. Choice B keeps Group 5 in and averages all six groups. Choice C averages the shares of air left instead of the shares used up. Choice D is the modern value, 20.95, rounded; it is not the class result.
Question 11 of 20 · Multiple Choice
In Diagram 2, which finding is farthest from the modern value for oxygen in dry air?
Answer: C
Measured from the modern 20.95 percent, Lavoisier's stated 27 is about 6.05 points away, his mercury result of about 16.7 is about 4.3 points away, and Cavendish's 20.84 is only 0.11 away. The scale starts at zero, so the bar heights can be compared directly. Choice A is the second farthest. Choice B is the closest. Choice D ignores the scale.
Question 12 of 20 · Multiple Choice
In T1, paragraph 2, Lavoisier says he "was obliged to repeat this experiment several times" and will "give in one detail the results of two or three experiments of the same nature." Why does this matter when you compare his numbers with another source?
Answer: D
Lavoisier says it was hard "in one experiment both to preserve the whole air upon which we operate, and to collect the whole of the red particles," so he reports several runs as one. That is honest, but it means the account's numbers are a summary, which is one reason to expect them to differ from a single careful measurement. Choice A is not in the text. Choice B is the opposite of what he says. Choice C goes too far: repeated runs make a finding more trustworthy, not worthless.
Question 13 of 20 · Multiple Choice
T1, paragraph 3, says the air left after the experiment "was no longer fit either for respiration or for combustion." Which observation from the class steel-wool test would support this finding?
Answer: B
Lavoisier's test of the leftover air was a flame: "when a taper was plunged into it, it was extinguished." The class report says the air left in the tubes "put out a burning splint when our teacher tested one tube," the same test with the same result. Choice A shows that part of the air was used up, not what the rest is like. Choice C shows that rust formed. Choice D shows that the reaction had finished.
Question 14 of 20 · Multiple Choice
In T2, Ramsay says Cavendish's result "does not differ materially" from the best modern analyses. By how many percentage points do the two figures for oxygen differ?
Answer: A
Cavendish found 20.84 percent and the modern analyses 20.96 percent, and 20.96 - 20.84 = 0.12 points, which is why Ramsay calls the difference not material. The nitrogen figures differ by the same amount, 79.16 - 79.04 = 0.12. Choice B moves the decimal point. Choice C subtracts the oxygen figure from the nitrogen figure (79.16 - 20.84 ≈ 58.3). Choice D reverses the digits of the answer.
Question 15 of 20 · Short Answer
T4, paragraph 3, says atmospheric air "is composed of two elastic fluids of different and opposite qualities." Does the class steel-wool test (T3) support or contradict this finding? Explain, using one detail from T3 and one from T4.
Model answer: It supports it. In T3, rusting iron used up about a fifth of the air and "the air left in the tubes put out a burning splint," so the leftover part behaves differently from the whole air. In T4, the respirable gas made a taper burn "with a dazzling splendour" while the leftover "mephitis" is "incapable of supporting combustion," the same opposite qualities. The support is partial: the class test shows that part of the air is used up and the rest does not support burning, but it does not show that the rest is only one gas. Rubric: full credit for a correct judgment with one detail from each text and a limit; partial credit for a judgment with evidence from one text only.
Question 16 of 20 · Short Answer
Modern chemistry gives the red calx as mercury(II) oxide, HgO, which is 92.6 percent mercury by mass. Compare this with Lavoisier's weights in T4, paragraph 1. Does the modern figure support or contradict his finding?
Model answer: Lavoisier got 41 1/2 grains of mercury from 45 grains of calx, and 41.5 ÷ 45 ≈ 0.922, or 92.2 percent mercury. The modern figure predicts 0.926 × 45 ≈ 41.7 grains. The two differ by less than half a percentage point, about 0.2 grains, so the modern figure supports his finding, especially given that he says it was hard to collect all of the red particles. Rubric: full credit for the percentage (or the predicted grains), the comparison and a judgment; partial credit for the arithmetic without a judgment.
Question 17 of 20 · Short Answer
At the end of Lavoisier's experiment, 42 of the original 50 cubic inches of air were left (T4, paragraph 3, and T1). If the air were 79.05 percent unbreathable gas, as the modern table implies, how much should have been left? What does the comparison suggest?
Model answer: 0.7905 × 50 ≈ 39.5 cubic inches should have been left, but 42 were left, about 2.5 cubic inches more. The leftover air still held some oxygen, which is the explanation Lavoisier himself gives in paragraph 4. The modern figure and Lavoisier's explanation support each other; his mercury experiment simply did not finish the job. Rubric: full credit for the 39.5, the comparison and the link to paragraph 4; partial credit for the arithmetic alone.
Question 18 of 20 · Short Answer
T3 ends: "So air is about 20 percent oxygen, and Lavoisier was wrong." Rewrite this conclusion so that it matches the evidence. Say which of Lavoisier's findings the class result contradicts and which it supports.
Model answer: "Rusting iron used up about a fifth of the air in five tubes, close to Cavendish's 20.84 percent and the modern 20.95. This contradicts Lavoisier's stated proportion of 27 parts in 100 and is higher than his mercury result of about one sixth, but it supports his finding that air has a part that metals take up and a part that does not support burning." The original says "wrong" about everything Lavoisier found, when the class result agrees with his main finding. Rubric: full credit for a rewritten conclusion that names one finding contradicted and one supported; partial credit for softening the wording without naming both.
Question 19 of 20 · Short Answer
Name one difference between the methods of Cavendish (T2) and the class steel-wool test (T3) that should make Cavendish's figure more trustworthy, and one reason the class test is still worth comparing with it.
Model answer: Cavendish "analysed the air collected on sixty days" with an instrument he had made "capable of giving more accurate results," while the class read five usable tubes once, with a ruler, after three days. Many careful measurements are more trustworthy than a few rough ones. The class test is still worth comparing because it uses a completely different method, rusting iron instead of nitric oxide, and still lands within about one and a half percentage points; agreement between different methods is strong support. Rubric: full credit for one method difference quoted from T2 and one reason the comparison is useful; partial credit for one of the two.
Question 20 of 20 · Short Answer
Using at least three sources on this page, write three or four sentences that compare and contrast their findings on how much of the air is oxygen, and name one earlier explanation or account that these findings contradict.
Model answer: Lavoisier's mercury experiment used up about one sixth of the air (T1), while Cavendish's analyses found 20.84 percent oxygen (T2) and the class steel-wool test about a fifth (T3). All three agree that only part of the air is used up and that the rest does not support burning; they contrast on the size of that part, and the two methods that ran to completion agree best with the modern 20.95 percent. Together they contradict the old account that air is a single element, and Cavendish's sixty days of results contradict the claim that sea air holds more vital air than town air. Rubric: full credit for three sources with numbers, a likeness, a difference and a named account contradicted; partial credit for two sources or no named account.
0 of 20 answered · 0 correct
06
Frequently Asked Questions
10 Questions
What does RST.9-10.9 mean?
RST.9-10.9 asks students in grades 9-10 to set the findings of a science text beside findings from other sources, including their own experiments. They say where the findings agree and where they differ, and whether the findings support or contradict an earlier explanation or account.
What counts as a "finding" in a science text?
A finding is what was measured or observed, with its numbers and conditions, such as "the trapped air lost about one sixth of its volume." It is different from the author's conclusion or explanation, which says what the finding means. Students should compare findings with findings before they compare explanations.
Do students have to run their own experiment for RST.9-10.9?
Yes, the standard names students' own experiments as one of the other sources. The experiment can be short and simple, like the steel-wool test on this page, as long as its findings answer the same question as the text. When a class cannot run it, a sample data set is a fallback, not a replacement.
How is RST.9-10.9 different from RST.11-12.9?
RST.9-10.9 asks students to compare and contrast findings and to say when they support or contradict earlier accounts. RST.11-12.9 goes further: students synthesize information from a range of sources into one coherent understanding of a process or concept and resolve conflicting information where possible.
What is the difference between "support" and "prove"?
A finding supports an explanation when it is what the explanation predicts; it does not prove the explanation, because another explanation might predict the same thing. Students should write "supports" or "contradicts" and say how strongly, and save "proves" for mathematics.
What if my class results do not match the textbook value?
That is useful, not a failure. Compare the methods first: an unfinished reaction, a missed step or a reading error explains most gaps. A class result should change your view of a published finding only when the class method is at least as careful and the gap is larger than the errors you can estimate.
Why use eighteenth-century texts to teach a modern skill?
Old texts show findings being compared while the explanation was still in dispute. Lavoisier, Cavendish and Rayleigh measured the same air by different methods and reached findings that supported one account and contradicted another, which is the exact move RST.9-10.9 asks students to make.
What mistakes do students often make with RST.9-10.9?
Four are frequent. They compare numbers that answer different questions, they call a source wrong without checking its method, they ignore errors in their own experiment, and they say a single result proves or disproves a theory. The four-step routine in this lesson addresses each one.
How is RST.9-10.9 assessed?
Reading tests often pair a short science passage with a table, a graph or the description of an experiment, and ask which statement correctly compares them or whether the new data support the passage. In class, a short written comparison of a text and the students' own results, with a judgment, is the most direct evidence of the skill.
Which science courses use RST.9-10.9?
It fits any course with labs and readings, most often chemistry, biology and physical science. Any lab where students compare their results with a textbook, a published study or a historical experiment is a chance to practice it.
07
Related Standards
5 standards
These standards connect to RST.9-10.9: prerequisites to review first, parallel standards at the same level, and next steps that build on it.
Before this lesson
RST.6-8.9Prerequisite
Compare information from experiments, simulations or media with a text on the same topic
Lesson coming soon
Alongside
RST.9-10.8Parallel
Assess how far a text's reasoning and evidence support its claim or recommendation