RST.11-12.8Common CoreELALiteracy in Science and Technical SubjectsGrades 11-12
RST.11-12.8: Evaluating Hypotheses, Data, Analysis and Conclusions in Science Texts
In plain English: RST.11-12.8 is the Common Core ELA standard that asks students in grades 11-12 to evaluate the hypotheses, data, analysis and conclusions in a science or technical text. Students verify the data by redoing the text's own numbers when they can, and corroborate or challenge the conclusions with other sources. It is usually taught in chemistry, physics and other advanced science courses.
Evaluate the hypotheses, data, analysis, and conclusions in a science or technical text, verifying the data when possible and corroborating or challenging conclusions with other sources of information.
Common Core State Standards for English Language Arts & Literacy · Domain: Reading Standards for Literacy in Science and Technical Subjects 6-12 · Cluster: Integration of Knowledge and Ideas · Official standard
A science report makes a chain of moves: it proposes a hypothesis, collects data, analyzes them and draws conclusions. RST.11-12.8 asks students to evaluate every link in that chain, to verify the data when the text gives enough numbers to redo, and to corroborate or challenge the conclusions with other sources of information. This lesson teaches a part-by-part evaluation (Diagram 1) and two checks that cut across it: recomputing from the text's own figures, and weighing other sources by how independent their methods are.
Students work with Marie Curie's doctoral thesis, in the English translation of 1904: the minerals that led her to propose a new element, her determination of the atomic weight of radium, with the weighings behind it, and her account of its spectrum. Ernest Rutherford's textbook of 1905 reports the same work and a competing value, and a modern lab report written for this page gives students a study whose arithmetic and conclusion they can correct.
Learning Objectives
By the end of this lesson, students will be able to:
Evaluate a hypothesis: what data it grows from, how cautiously it is stated and what it predicts
Evaluate data and analysis, including controls, stated assumptions and the limits of the measurements
Verify data when possible by recomputing results from a text's own figures, and explain what a discrepancy does and does not show
Corroborate or challenge a conclusion with other sources, giving more weight to independent methods
Judge whether a conclusion stays within its data, and state a supported verdict
Prior Knowledge Required
Students should already be comfortable with:
Assessing how far reasoning and evidence support a claim in a science text RST.9-10.8
Comparing findings in a text with those of other sources RST.9-10.9
Ratios, means and percentage differences
Atoms, elements and chemical formulas from a first chemistry or physical science course
Project this invented news brief: "A new study of 40 volunteers found that people who drank green tea every day for 12 weeks lost 2 kg more than people who did not. Green tea burns fat."
Warm-Up Prompt
Before you accept the last sentence, what would you want to know about the study's hypothesis, its data, its analysis and its conclusion? Name one thing you could check yourself and one other source you would look for.
Take answers and sort them into the four parts of Diagram 1. Hypothesis: was it stated before the study? Data: how were the groups chosen, and how was weight measured? Analysis: is 2 kg an average, and how much did people vary? Conclusion: "burns fat" names a cause the study did not measure. Students can check the arithmetic if the brief gives the group averages, and they can look for other studies. Tell students that this is today's skill. RST.11-12.8 asks them to evaluate the hypotheses, data, analysis and conclusions in a science or technical text, verifying the data when possible and corroborating or challenging conclusions with other sources of information.
Direct Instruction15-20 minutes
Part 1: Four parts, two checks. Post Diagram 1 for the whole lesson. Students evaluate each part of a study in turn: the hypothesis (the proposed explanation and what it predicts), the data (what was measured and how), the analysis (what was done to the data) and the conclusions (what the author says it all shows). Two checks cut across the parts. To verify the data is to redo the numbers from the text's own figures. To corroborate or challenge a conclusion is to compare it with other sources: another experiment, another method, a reference value or later work. Agreement from a different method is stronger than agreement from a repeat of the same one.
Part 2: Model with Curie (T1). In 1898 Marie Curie measured how strongly different substances made air conduct electricity, the effect of the rays we now call radioactivity. Her instrument gave a current: the larger the current, the more active the sample. Uranium compounds were known to be active in proportion to the uranium they contain. Gloss before reading: "pitchblende" is the main ore of uranium, "chalcolite" and "autunite" are uranium minerals, and "simple bodies" means chemical elements. Read T1 aloud, then show the rows of Curie's table below it and work the two examples.
1I have examined many minerals in my apparatus; certain of them gave evidence of radio-activity, e.g., pitchblende, thorite, orangite, fergusonite, cleveite, chalcolite, autunite, monazite, &c. The following is a table giving in ampères the intensity, i, of the current obtained with metallic uranium and with different minerals:—
[...]
2All the minerals which showed radio-activity contained uranium or thorium: their activity is therefore not surprising, but the intensity of the action in certain cases is unexpected. Thus pitchblendes (ores of uranium oxide) are found which are four times as active as metallic uranium. Chalcolite (double phosphate of copper and uranium) is twice as active as uranium. Autunite (phosphate of uranium and calcium) is as active as uranium. These facts do not accord with previous conclusions, according to which no mineral should be so active as thorium or uranium.
3To throw light on this point, I prepared artificial chalcolite by the process of Debray, starting with the pure products. The process consists in mixing a solution of uranium nitrate with a solution of copper phosphate in phosphoric acid and warming to 50° or 60°. After some time, crystals of chalcolite appear in the liquid.
4Chalcolite thus obtained possesses a perfectly normal activity, given by its composition; it is two and a-half times less active than uranium.
5It therefore appeared probable that if pitchblende, chalcolite, and autunite possess so great a degree of activity, these substances contain a small quantity of a strongly radio-active body, differing from uranium and thorium and the simple bodies actually known. I thought that if this were indeed the case, I might hope to extract this substance from the ore by the ordinary methods of chemical analysis.
Marie Curie, Radio-Active Substances (radio-active minerals and the hypothesis of a new element; excerpt, cut marked [...]) (1903; this edition 1904). Public domain (published 1904). Source text.
From Curie's table in T1: current produced by metallic uranium and by uranium minerals, in units of 10⁻¹¹ ampere (values as printed; thorium and rare-earth minerals left out; carnotite, a uranium mineral, is the last row of her table, after the rare-earth minerals)
Substance
i × 10¹¹
Uranium
2·3
Pitchblende from Johanngeorgenstadt
8·3
Pitchblende from Joachimsthal
7·0
Pitchblende from Pzibran
6·5
Pitchblende from Cornwallis
1·6
Cleveite
1·4
Chalcolite
5·2
Autunite
2·7
Carnotite
6·2
Evaluating a hypothesis (T1, paragraphs 2 and 5)
State Curie's hypothesis in your own words. Is it well grounded in her data, and how carefully does she word it?
Result: The hypothesis (paragraph 5): the very active minerals "contain a small quantity of a strongly radio-active body, differing from uranium and thorium and the simple bodies actually known," that is, an unknown element. It is grounded in an anomaly in the data: if activity depends only on the uranium present, no uranium mineral should be more active than uranium metal, yet paragraph 2 reports minerals that are. The wording is careful: "It therefore appeared probable" and "if this were indeed the case" mark it as a proposal still to be tested, not a finding. A strong hypothesis also says what would follow if it is true; paragraph 5 names that consequence in its last sentence.
Verifying the data (T1, paragraph 2, and the table)
Paragraph 2 says chalcolite "is twice as active as uranium" and autunite "is as active as uranium." Check both statements against the table.
Result: Activity is compared through the current. Chalcolite: 5·2 ÷ 2·3 ≈ 2.26, so "twice" is a fair rounding. Autunite: 2·7 ÷ 2·3 ≈ 1.17, so "as active as" is loose: autunite gave about 17 percent more current than uranium metal. Both statements are supported in direction; the second is stated less exactly than the data allow. Verifying also means noticing what the table cannot tell you: the currents come from one apparatus and depend on how each sample was spread (in a paragraph left out of T1, Curie notes that the current from orangite rose with the thickness of the layer), so small differences deserve less weight than large ones.
Close the model by naming the pattern. Curie's hypothesis grew out of data that did not fit an accepted rule, and it is worded as a proposal. The data mostly check out when verified. What the text has not yet done is test the hypothesis; paragraphs 3-4 describe a step she took before announcing it, which students will evaluate in the quiz. Diagram 2 draws these rows of the table to scale.
Guided Practice15-20 minutes
Pairs read the lab report (T2), a modern text written for this page, and mark the hypothesis, data, analysis and conclusion in the margin. Then use the reference table below it, a second source, to work the two examples as a class.
1Hypothesis. Our unknown metal cylinder is aluminum, because it is silver-gray and feels light for its size. If it is aluminum, its specific heat should be close to 0.90 J/(g·°C) and its density close to 2.70 g/cm³. Specific heat is the energy needed to warm 1 gram of a substance by 1 °C. (The class, the cylinder and the data in this report are invented for teaching.)
2Method. We heated the 60.0 g cylinder in boiling water for 5 minutes; the water read 100.0 °C. We then moved it quickly into a foam-cup calorimeter holding 100.0 g of water at 20.0 °C, stirred, and recorded the highest temperature. We ran three trials, drying the cylinder and starting with fresh water each time. To find the volume, we lowered the cylinder into a graduated cylinder of water.
3Data. Highest temperatures: trial 1, 29.0 °C; trial 2, 28.7 °C; trial 3, 29.2 °C. The water in the graduated cylinder rose from 50.0 mL to 72.5 mL.
4Analysis. The heat lost by the metal equals the heat gained by the water, so c = (100.0 × 4.18 × rise of the water) ÷ (60.0 × fall of the metal), where 4.18 J/(g·°C) is the specific heat of water. Trial 1: c = (100.0 × 4.18 × 9.0) ÷ (60.0 × 71.0) = 0.883. Trial 2: c = 0.805. Trial 3: c = 0.905. Mean: 0.864 J/(g·°C). Density: 60.0 g ÷ 22.5 cm³ = 2.67 g/cm³.
5Conclusion. Our mean specific heat, 0.864 J/(g·°C), is within 4 percent of the value for aluminum, 0.897, and our density, 2.67 g/cm³, matches aluminum's 2.70. This proves that the cylinder is pure aluminum. The small difference in specific heat was caused by human error.
Written for this page (the class, the cylinder and the data are invented), Lab Report: Is Our Unknown Metal Aluminum? (student report, invented data). Original passage written for this page.
Another source: standard reference values for six metals near room temperature
Metal
Specific heat (J/(g·°C))
Density (g/cm³)
Aluminum
0.897
2.70
Magnesium
1.02
1.74
Titanium
0.523
4.51
Zinc
0.388
7.14
Iron
0.449
7.87
Copper
0.385
8.96
Verifying the analysis (T2, paragraphs 3-4)
Recompute the specific heat for trials 2 and 3 and the mean. Does the report's analysis hold?
Result: Trial 2: the water rose 28.7 - 20.0 = 8.7 °C and the metal fell 100.0 - 28.7 = 71.3 °C, so c = (100.0 × 4.18 × 8.7) ÷ (60.0 × 71.3) = 3,636.6 ÷ 4,278 ≈ 0.850, not 0.805. Trial 3: (100.0 × 4.18 × 9.2) ÷ (60.0 × 70.8) = 3,845.6 ÷ 4,248 ≈ 0.905, as reported. The corrected mean is (0.883 + 0.850 + 0.905) ÷ 3 ≈ 0.879, not 0.864. The density also checks: 72.5 - 50.0 = 22.5 cm³, and 60.0 ÷ 22.5 ≈ 2.67 g/cm³. The error is in the analysis, not the data, and fixing it moves the result closer to aluminum: 0.879 is 2 percent below 0.897.
Corroborating and challenging the conclusion (T2, paragraph 5, and the reference table)
Use the reference table to judge the conclusion. Which parts are corroborated, and which are challenged?
Result: Corroborated: two independent properties, specific heat and density, both point to aluminum, and no other metal in the table comes close on either (magnesium, the next lightest, has a density of 1.74 and a specific heat of 1.02). Agreement on two unrelated measurements is much stronger than agreement on one. Challenged: "proves that the cylinder is pure aluminum" goes beyond the data, because common aluminum alloys have almost the same density and specific heat, so these tests cannot tell pure aluminum from an alloy. "Human error" names no cause. Heat lost to the cup and the air while the cylinder is moved would make the water rise too little and c come out low, which fits the direction of the gap. A strong conclusion would say: "The data are consistent with aluminum or an aluminum alloy."
Debrief: Which part of the report was weakest: the hypothesis, the data, the analysis or the conclusion? Students usually find that the hypothesis (it makes two testable predictions) and the data are sound, the analysis has one arithmetic slip, and the conclusion overreaches. Evaluation is part by part; one weak part does not sink the whole report.
Independent Practice20 minutes
Students read Curie's account of the atomic weight of radium (T3), with its three tables, and Rutherford's account of the same work a year later (T4), and answer quiz questions 1-20. Questions 1-8 and 15-16 use T3 and its tables; questions 9-12, 17 and 20 use T4 with T3; questions 13, 14, 18 and 19 use T1 in Direct Instruction, with its table and Diagram 2. Tell students before they read: the atomic weight is the mass of an atom on the scale then in use, with hydrogen near 1; Curie found it by dissolving a weighed amount of radium chloride and weighing the silver chloride it formed, and "bivalent" or "divalent" means that each atom combines with two chlorine atoms. In the source's numbers the raised dot is a decimal point: 0·1150 means 0.1150.
1I employed the classic method of weighing as silver chloride the chlorine contained in a known weight of the anhydrous chloride. As control experiment, I determined the atomic weight of barium by the same method, under the same conditions, and with the same quantity of material, first 0·5 grm. and then 0·1 grm. The figures obtained were always between 137 and 138. I thus saw that the method gives satisfactory results, even with a very small quantity of material.
2The first two determinations were made with chlorides, of which one was 230 times and the other 600 times as active as uranium. These two experiments gave the same figure as the experiment with the pure barium chloride. There was therefore no hope of finding a difference except by using a much more active product. The following experiment was made with a chloride, the activity of which was about 3500 times as great as that of uranium; and this experiment enabled me, for the first time, to observe a small but distinct difference; I found, as the mean atomic weight of the metal contained in this chloride, the number 140, which showed that the atomic weight of radium must be higher than that of barium. By using more and more active products, and obtaining spectra of radium of increasing intensity, I found that the figures obtained rose in proportion, as is seen in the following table (p. 28).
3The figures of column A must only be looked upon as a rough estimate. The calculation of the activity of strongly radio-active bodies is difficult, for many reasons which will be discussed later.
[...]
4A represents the activity of the chloride, that of uranium being unity; M the atomic weight found.
5At the termination of the processes described above, I obtained, in March, 1902, 0·12 grm. of radium chloride, of which Demarçay made the spectral analysis. This radium chloride, in the opinion of Demarçay, was fairly pure; its spectrum, however, showed the three principal barium lines with considerable intensity. I made four successive estimations of the chloride, the results of which as follows:—
[...]
6I then re-purified this chloride, and obtained a much purer substance, in the spectrum of which the two strongest barium lines were very faint. Given the sensitiveness of the spectrum reaction of barium, Demarçay estimated that the purified chloride contained only the merest traces of barium, incapable of influencing the atomic weight to an appreciable extent. I made three determinations with this perfectly pure radium chloride. The results were as follows:—
[...]
7The mean of these numbers is 225. They were calculated in the same way as the preceding ones by considering radium as a bivalent element, the chloride having the formula RaCl₂, and taking for silver and chlorine the values Ag = 107·8, Cl = 35·4.
8Hence the atomic weight of radium is Ra = 225.
[...]
9From its chemical properties, radium is an element of the group of alkaline earths, being the member next above barium.
10From its atomic weight also, radium takes its place in Mendeleeff’s table after barium with the alkaline earth metals, in the row which already contains uranium and thorium.
Marie Curie, Radio-Active Substances (determining the atomic weight of radium; excerpt, cuts marked [...]) (1903; this edition 1904). Public domain (published 1904). Source text.
Curie's first table in T3 (the first [...]): activity of the chloride and atomic weight found, with her notes
A (activity, uranium = 1)
M (atomic weight found)
Curie's note
3500
140
Spectrum of radium faint.
4700
141
7500
145·8
Spectrum of radium strong, but that of barium predominating.
Order of magnitude, 10⁶
173·8
The two spectra of almost equal intensity.
Order of magnitude, 10⁶
225
Only a trace of barium present.
Curie's second table in T3 (the second [...]): the fairly pure chloride of March 1902, masses in grams
Estimation
Anhydrous radium chloride
Silver chloride
M
I.
0·1150
0·1130
220·7
II.
0·1140
0·1119
223·0
III.
0·11135
0·1086
222·8
IV.
0·10925
0·10645
223·1
Curie's third table in T3 (the third [...]): the re-purified chloride, masses in grams
Estimation
Anhydrous radium chloride
Silver chloride
M
I.
0·09192
0·08890
225·3
II.
0·08936
0·08627
225·8
III.
0·08839
0·08589
224·0
114. Atomic weight of radium. Mme Curie has made successive determinations of the atomic weight of the new element with specimens of steadily increasing purity. In the first observation the radium was largely mixed with barium, and the atomic weight obtained was the same as that of barium, 137·5. In successive observations with specimens of increasing purity the atomic weights of the mixture were 146 and 175. The final value obtained recently was 225, which may be taken as the atomic weight of radium on the assumption that it is divalent.
2In these experiments about 0·1 gram of pure radium chloride was obtained by successive fractionations. The difficulty involved in preparing a quantity of pure radium chloride large enough to test the atomic weight may be gauged from the fact that only a few centigrams of fairly pure radium, or a few decigrams of less concentrated material, are obtained from the treatment of about 2 tons of the mineral from which it is derived.
3Runge and Precht have examined the spectrum of radium in a magnetic field, and have shown the existence of series analogous to those observed for calcium, barium, and strontium. These series are connected with the atomic weights of the elements in question, and Runge and Precht have calculated by these means that the atomic weight of radium should be 258—a number considerably greater than the number 225 obtained by Mme Curie by means of chemical analysis. Marshall Watts, on the other hand, using another relation between the lines of the spectrum, deduced the value obtained by Mme Curie. Runge has criticised the method of deduction employed by Marshall Watts on the ground that the lines used for comparison in the different spectra were not homologous. Considering that the number found by Mme Curie agrees with that required by the periodic system, it is advisable in the present state of our knowledge to accept the experimental number rather than the one deduced by Runge and Precht from spectroscopic evidence.
4There is no doubt that radium is a new element possessing remarkable physical properties. The detection and separation of this substance, existing in such minute proportions in pitchblende, has been due entirely to the characteristic property we are considering, and is the first notable triumph of the study of radio-activity. As we shall see later, the property of radio-activity can be used, not only as a means of chemical research, but also as an extraordinarily delicate method of detecting chemical changes of a very special kind.
Ernest Rutherford, Radio-Activity (article 14: the atomic weight of radium; excerpt) (1904; this edition 1905). Public domain (published 1905). Source text.
Closure5 minutes
Exit ticket: "Pick one number or conclusion from today's texts. Say whether you verified it, corroborated it, challenged it, or could not check it, and name the source or calculation you used." Sort the tickets into "checked with a calculation," "checked against another source" and "accepted without a check" to plan the next lesson.
Teacher note on the historical texts. T1, T3 and T5 are an English translation, published in 1904, of Marie Curie's 1903 doctoral thesis; T4 and T6 are from Ernest Rutherford's textbook of 1905. Their units and values are of their time: atomic weights were measured against a scale then in use, Curie takes chlorine as 35·4 and silver as 107·8 (today 35.45 and 107.87), and wavelengths appear in µµ (today nanometers) and Ångström units. The mass of radium-226, the isotope Curie isolated, is 226.03 on today's scale. Radium is intensely radioactive and was later found to harm the people who handled it; Curie's death in 1934 is generally attributed to her long exposure to radiation. No radioactive material is used in this lesson. The texts contain no dated or offensive language.
Homework passages. The homework compares Curie's and Rutherford's accounts of the spectrum of radium, below, with their tables of lines.
1It was of the first importance to check, by all possible means, the hypothesis, underlying this work, of new radio-active elements. In the case of radium, spectrum analysis was the means of confirming this hypothesis.
2M. Demarçay undertook the examination of the new radio-active bodies by the searching methods which he employs in the study of photographic spark spectra.
3The assistance of so competent a scientist was of the greatest value to us, and we are deeply grateful to him for having consented to take up this work. The results of the spectrum analysis brought conviction to us when we were still in doubt as to the interpretation of the results of our research.
4The first specimens of fairly active barium chloride containing radium, examined by M. Demarçay, exhibited together with the barium lines a new line of considerable intensity and of wave-length λ = 381·47 µµ in the ultra-violet. With the more active products prepared subsequently, Demarçay saw the line 381·47 µµ more distinctly; at the same time other new lines appeared, and the intensity of the new lines was comparable with that of the barium lines. A further concentration furnished a product for which the new spectrum predominated, and the three strongest barium lines, alone visible, merely indicated the presence of this metal as an impurity. This product may be looked upon as nearly pure radium chloride. Finally, by further purification, I obtained an exceedingly pure chloride, in the spectrum of which the two chief barium lines were scarcely visible.
5The following is a list, according to Demarçay, of the principal radium lines for the portion of the spectrum included between λ = 500·0 and λ = 350·0 µµ. The intensity of each line is represented by a figure, the strongest being marked 16:—
[...]
6According to Demarçay, the position of radium may be among the bodies possessing the most sensitive spectrum reaction. I also have concluded from the work of concentration, that in the first specimen examined, which showed clearly the line 3814·7, the proportion of radium must have been very small (perhaps about 0·02 per cent). Nevertheless, an activity fifty times as great as that of metallic uranium is required in order to distinguish clearly the principal radium line in the spectra photographed. With a sensitive electrometer the radio-activity of a substance only 1/100 of that of metallic uranium can be detected. It is clear that, in order to detect the presence of radium, the property of radio-activity is several thousand times more sensitive than the spectrum reaction.
Marie Curie, Radio-Active Substances (the spectrum of radium; excerpt, cut marked [...]) (1903; this edition 1904). Public domain (published 1904). Source text.
Demarçay's radium lines as listed by Curie in T5 (the [...]): wavelength λ in µµ and intensity (strongest = 16)
λ (µµ)
Intensity
482·63
10
472·69
5
469·98
3
469·21
7
468·30
14
464·19
4
460·03
3
453·35
9
443·61
8
434·06
12
381·47
16
364·96
12
113. Spectrum of radium. It was of great importance to settle as soon as possible whether radium was in reality modified barium or a new element with a definite spectrum. For this purpose the Curies prepared some specimens of radium chloride, and submitted them for examination of their spectrum to Demarçay, an authority on that subject. The first specimen of radium chloride examined by Demarçay was not very active, but showed, besides the lines due to barium, a very strong new line in the ultra-violet. In another sample of greater activity, the line was still stronger and others also appeared, while the intensity of the new lines was comparable with those present due to barium. With a still more active specimen which was probably nearly pure, only three strong lines of barium appeared, while the new spectrum was very bright. The following table shows the wave-length of the new lines observed for radium. The wave lengths are expressed in Ångström units and the intensity of each ray is denoted by a number, the ray of maximum intensity being 16.
[...]
2The lines are all sharply defined, and three or four of them have an intensity comparable with any known lines of other substances. There are also present in the spectrum two strong nebulous bands. In the visible part of the spectrum, which has not been photographed, the only noticeable ray has a wave length 5665, which is, however, very feeble compared with that of wave length 4826·3. The general aspect of the spectrum is similar to that of the alkaline earths; it is known that these metals have strong lines accompanied by nebulous bands.
3The principal line due to radium can be distinguished in impure radium of activity 50 times that of uranium. By the electrical method it is easy to distinguish the presence of radium in a body which has an activity only ¹⁄₁₀₀ of uranium. With a more sensitive electrometer ¹⁄₁₀₀₀₀ of the activity of uranium could be observed. For the detection of radium, the examination of the radio-activity is thus a process nearly a million times more sensitive than spectrum analysis.
4Later observations on the spectrum of radium have been made by Runge, Exner and Haschek, with specimens of radium prepared by Giesel. Crookes has photographed the spectrum of radium in the ultra-violet, while Runge and Precht, using a highly purified sample of radium, observed a number of new lines in the spark spectrum. It has been mentioned already that the bromide of radium gives a characteristic pure carmine-red coloration to the Bunsen flame. The flame spectrum shows two broad bright bands in the orange-red, not observed in Demarçay’s spectrum. In addition there is a line in the blue-green and two feeble lines in the violet.
Ernest Rutherford, Radio-Activity (article 13: the spectrum of radium; excerpt, cut marked [...]) (1904; this edition 1905). Public domain (published 1905). Source text.
Rutherford's table of the new radium lines in T6 (the [...]): wavelength in Ångström units and intensity (strongest = 16)
Wave length (Å)
Intensity
4826·3
10
4726·9
5
4699·6
3
4692·1
7
4683·0
14
4641·9
4
4600·3
3
4533·5
9
4436·1
6
4340·6
12
3814·7
16
3649·6
12
Differentiation Strategies
For Struggling Students
Give a four-row organizer (hypothesis, data, analysis, conclusions) with one guiding question per row from Diagram 1
Provide the relation for the atomic weight with the numbers of one row already placed, so students only calculate
Pre-teach the older terms (pitchblende, bivalent, µµ, the raised decimal point) with a glossary card
For Advanced Students
Estimate how much barium, as a percentage of the chloride, would lower a true 226 to the 225 Curie found, and judge whether Demarçay's "merest traces" could do it
Read the full section on the spectrum in both sources and write a one-page reviewer's report on the claim that radium is an element
Find a current study summarized in the news, read the original abstract, and evaluate the news story's conclusion against it
Assessment Guidance
What to Look For
Strong evaluations take the text part by part, quote the hypothesis and the conclusion exactly, and redo at least one number from the text's own figures. Strong answers name stated assumptions (such as bivalence) and ask what the conclusion depends on, and they weigh other sources by method, not just by agreement. Watch for students who accept a conclusion because the arithmetic checks out, who count repeats of one method as independent corroboration, who treat a single discrepancy as proof that a whole study is wrong, and who judge a 1903 study by what was learned later without saying so.
02
Classroom Activities
3 Activities
1
Check the Numbers
15 minGroups of 3
Four stations, each with a short claim and the numbers behind it (written for this page; all data are invented). At each station the group verifies the data, then writes one sentence: "The numbers support / do not support the conclusion, because ____."
The 4 Station Cards
Vaccine trial: 20,000 volunteers in each group. 9 people in the vaccine group and 180 in the placebo group became ill. The press release says the vaccine is 95 percent effective.
Reaction-rate lab: a reaction took 120 s at 20 °C, 64 s at 30 °C and 31 s at 40 °C. The report concludes that the rate doubles for every 10 °C rise.
Tide gauge: sea level at a harbor rose 34 mm in 10 years. An article says that at this rate the sea there will be 1 meter higher in 80 years.
Solar panel ad: "Our new panel is 25 percent more efficient: it makes 400 W, where the old model made 320 W." The new panel has an area of 1.95 m², the old one 1.60 m².
Teacher Key
Station 1: Supported. With equal groups, efficacy = 1 - 9 ÷ 180 = 0.95, so 95 percent checks out.
Station 2: Supported for these two steps. Rate is proportional to 1 ÷ time: 120 ÷ 64 ≈ 1.9 and 64 ÷ 31 ≈ 2.1, so the rate about doubles each 10 °C here. "For every 10 °C rise" goes beyond the three temperatures tested.
Station 3: Not supported. 34 mm in 10 years is 3.4 mm a year, and 3.4 × 80 = 272 mm, about 0.27 m. A meter in 80 years would need the rise to speed up, which these data do not show.
Station 4: Not supported as worded. The new panel makes 25 percent more power (400 ÷ 320 = 1.25) but it is also bigger. Per square meter, 400 ÷ 1.95 ≈ 205 W against 320 ÷ 1.60 = 200 W, only about 2.6 percent more: more power, not much more efficiency.
Discussion Questions
At which station was the arithmetic right but the conclusion still too broad?
Station 4 compares two numbers that are both correct. What made the claim misleading?
Which station would you most want corroborated by another source, and what source would you look for?
2
Peer Review Panel
15 minGroups of 4
Each group reviews a short invented study as a journal's reviewers would. Each member takes one part of Diagram 1 (hypothesis, data, analysis, conclusions) and writes two sentences on it; the group then recommends accept, revise or reject, with the one change that matters most.
The Study (invented)
Does background music improve memory? Hypothesis: students remember more words when they study with music playing. Method: 24 volunteers from one school studied a list of 30 words for 5 minutes; 12 chose to study with music through headphones and 12 chose silence. After 10 minutes, each wrote down every word they remembered. Results: the music group recalled a mean of 14.2 words and the silence group 12.1 words. Analysis: "The music group remembered 17 percent more words." Conclusion: "Music improves memory for all students, and schools should play music during study periods."
Teacher Key
Hypothesis: clear and testable, but it does not say what kind of music, which matters.
Data: the students chose their own group, so the groups may differ in other ways (for example, students who like studying with music may also be stronger at word lists). Twelve per group is small, and no spread is given.
Analysis: 14.2 ÷ 12.1 ≈ 1.17, so "17 percent more" checks out, but without the spread no one can tell whether a 2.1-word difference is larger than chance.
Conclusions: "for all students" and the school recommendation go far beyond 24 volunteers from one school. Revise: assign students to groups at random, report the spread, and limit the conclusion to the tested task.
Discussion Questions
The analysis checks out. Why is that not enough to accept the conclusion?
What other source would help you corroborate or challenge this conclusion?
Rewrite the conclusion so that the data support every word of it.
Variation: Author's Reply
Groups trade reviews and answer as the study's authors: accept each criticism, or explain why it does not apply.
3
Curie Then and Now
15 minPairs
Pairs compare five statements from Curie's thesis (T1 and T3) with a card of modern reference facts, a later source, and label each statement corroborated, revised or challenged, with one sentence of reasoning.
Curie's Statements and the Modern Card
Curie's statements:
Uranium and thorium compounds are active in proportion to the metal they contain (stated in the Direct Instruction introduction to T1).
Very active uranium minerals contain a small quantity of a new, strongly radio-active element (T1, paragraph 5).
The atomic weight of radium is 225 (T3, paragraph 8).
Radium belongs with the alkaline earth metals, next above barium (T3, paragraph 9).
Radium lies in the row that already contains uranium and thorium (T3, paragraph 10).
Modern reference card: Radioactivity comes from the nucleus of the atom and is almost entirely unaffected by chemical combination. Uranium ores contain radium, polonium and other radioactive elements formed as uranium decays. Radium has atomic number 88; its most stable isotope, radium-226, has a mass of 226.03 and a half-life of about 1,600 years. Radium is in group 2 of the periodic table, the alkaline earth metals, directly below barium, and in period 7, with actinium, thorium and uranium. Curie and André Debierne isolated radium as a metal in 1910.
Teacher Key
1: Corroborated, and explained: activity is a property of the atom's nucleus, so chemical form does not change it.
2: Corroborated. The extra activity comes from radium, polonium and other decay products of uranium in the ore.
3: Revised slightly: 225 then, 226.03 today, a small difference for samples of 0.1 g weighed with the constants of 1904.
4: Corroborated: group 2, directly below barium.
5: Corroborated: period 7 holds radium, actinium, thorium and uranium.
Discussion Questions
Statement 2 was a hypothesis in T1. Which later evidence turned it into a conclusion?
Does later corroboration mean Curie's evidence in 1903 was strong? Explain the difference.
Which statement depends on another one being right first?
03
Diagrams & Visual Aids
2 diagrams
Diagram 1: Evaluating a Science Text, Part by Part
The tool for the whole lesson. Evaluate the hypothesis, data, analysis and conclusions in turn, using the questions under each. Verify the data and the analysis by redoing the numbers from the text's own figures, and test the conclusions against other sources: other experiments, other methods, reference values and later work.
Diagram 2: Curie's Currents for Uranium and Uranium Minerals, Drawn to Scale
The uranium and uranium-mineral rows of Curie's table in T1, drawn as bars to scale (0-10, in units of 10⁻¹¹ ampere). The dashed line marks the current from metallic uranium, 2.3. The thorium and rare-earth minerals in her table are left out.
04
Homework Assignment
~30 min
RST.11-12.8 Homework: Two Accounts of the Spectrum of Radium
Directions: Use Curie's account of the spectrum of radium (T5) and Rutherford's account (T6), with their tables of lines, printed at the end of the Closure phase of the lesson plan (paragraphs are numbered). Curie gives wavelengths in µµ and Rutherford in Ångström units; 1 µµ (a nanometer) equals 10 Ångström units. Show every calculation, and name the source you use for every check.
Part 1: The Hypothesis and Its Test (Problems 1-2)
In T5, paragraph 1, Curie calls it "of the first importance to check, by all possible means, the hypothesis, underlying this work, of new radio-active elements," and says spectrum analysis confirmed it for radium. Explain what a new spectral line shows that measurements of activity alone could not. Then evaluate: does one new line confirm a new element, or only make it likely?
T5, paragraph 4, describes spectra of samples of increasing activity, from one new line beside the barium lines to a spectrum in which barium is "scarcely visible." Evaluate this sequence as evidence. Why is a change that follows the concentration stronger evidence than a single spectrum would be?
Part 2: Verifying the Data (Problems 3-4)
Convert every wavelength in Curie's table to Ångström units and compare it with Rutherford's table, line by line, including the intensities. List every place where the two tables disagree. For each, say whether it could be a rounding, a copying error or a real difference, and what source you would need to settle it.
Curie (T5, paragraph 6) says radio-activity is "several thousand times more sensitive than the spectrum reaction"; Rutherford (T6, paragraph 3) says "nearly a million times more sensitive." Verify each figure from the numbers each author gives. Do the two sources contradict each other? Is "nearly a million" supported by Rutherford's own numbers?
Part 3: Corroborating the Conclusion (Problems 5-6)
T6, paragraph 4, reports later observations by other scientists, some with radium prepared by Giesel rather than by the Curies, and a flame spectrum with bands "not observed in Demarçay's spectrum." Explain which of these later observations corroborate Curie's conclusion, and why samples from a different preparer count for more. Does the flame spectrum challenge Curie's account? Explain.
Write a paragraph of 8-10 sentences evaluating Curie's conclusion that radium is a new element. Discuss the hypothesis, the data and the analysis, include at least one check you verified yourself, and use at least two other sources on this page (T4, T6 or the atomic weight in T3) to corroborate or challenge the conclusion. End with your judgment of how strong the conclusion was by 1905.
Rubric
Criterion
Full Credit (2 pts)
Partial Credit (1 pt)
No Credit (0 pts)
Hypothesis and Data Evaluated
Explains what each piece of evidence tests and how strongly, with quotations
Describes the evidence without judging its strength
Restates the text only
Data Verified
Converts and compares every line, finds each disagreement, and checks both sensitivity figures with the arithmetic shown
Finds some disagreements or checks one figure
No checks, or checks with errors that change the result
Corroboration and Challenge
Uses at least two other sources, says which corroborate or challenge the conclusion, and weighs independent methods more
Uses one other source, or lists sources without weighing them
Uses no other source
Judgment
States a clear verdict on the conclusion tied to the evidence and names its limits
States a verdict with a general reason
No verdict
05
Quiz: 20 Questions
Interactive, with answers
Instructions
Questions 1-8 and 15-16 use Curie's account of the atomic weight of radium (T3) and its three tables, and questions 9-12, 17 and 20 use Rutherford's account (T4) with T3; both are in the Independent Practice phase of the lesson plan. Questions 13, 14, 18 and 19 use T1 in Direct Instruction, its table and Diagram 2 (paragraphs are numbered). Show your arithmetic and quote the words you rely on in the short answers. Your score updates as you answer, and Reset quiz clears everything so you or your students can try again.
Multiple choice: pick an option to check it. Short answer: write your answer, then reveal the model answer.
0 of 20 answered · 0 correct
Question 1 of 20 · Multiple Choice
In T3, paragraph 1, why did Curie determine the atomic weight of barium by the same method?
Answer: A
It is a control: the same method, "under the same conditions, and with the same quantity of material," applied to an element whose atomic weight was known. The results, "always between 137 and 138," match barium (137.33 today), so Curie could trust the method with samples of 0·1 grm. Choice B confuses the control with a measurement of impurity. Choice C reverses her finding: the later values rise far above barium's. Choice D describes a measurement of activity, which this paragraph does not make.
Question 2 of 20 · Multiple Choice
In T3, paragraph 2, the first two samples, 230 and 600 times as active as uranium, "gave the same figure as the experiment with the pure barium chloride." How does Curie interpret this result?
Answer: B
Curie writes: "There was therefore no hope of finding a difference except by using a much more active product." Her reasoning is that these samples were still almost all barium, so the little radium in them could not move the average atomic weight. The next sample, about 3500 times as active, gave 140, which supports that reading. Choice A takes a null result as a positive finding. Choice C is contradicted by the barium control in paragraph 1. Choice D ignores that the samples were active, which is how radium was traced.
Question 3 of 20 · Multiple Choice
Curie says the atomic weights "rose in proportion" as the activity rose (T3, paragraph 2, and her first table). Which evaluation of this analysis does the table best support?
Answer: D
M rises in every row (140, 141, 145·8, 173·8, 225) as A rises from 3500 to about 10⁶, so the trend is supported. But "in proportion" cannot mean a fixed ratio: A grows by a factor of hundreds while M grows by about 1.6. Curie also warns that "The figures of column A must only be looked upon as a rough estimate," so only the order of the rows is reliable. Choice A misreads the ratios. Choice B is false: M never falls. Choice C ignores column A, which the table does give.
Question 4 of 20 · Multiple Choice
Verify estimation I of the re-purified chloride (Curie's third table: 0·09192 g of radium chloride, 0·08890 g of silver chloride, M = 225·3). With Curie's values Ag = 107·8 and Cl = 35·4, each RaCl₂ gives two AgCl, so M + 70.8 = 2 × 143.2 × (mass of radium chloride) ÷ (mass of silver chloride). Which calculation reproduces her 225·3?
Answer: C
2 × 143.2 × 0.09192 ÷ 0.08890 ≈ 296.13, and 296.13 - 70.8 ≈ 225.3, the value Curie prints. Verifying one row this way shows that her table follows from her weighings. Choice B gives about 296.1, because it forgets to subtract the two chlorine atoms (70.8). Choice D gives about 112.7, because it counts one chlorine instead of two. Choice A gives about 206.2, because it swaps the two masses.
Question 5 of 20 · Multiple Choice
Now verify estimation II of the fairly pure chloride (Curie's second table: 0·1140 g, 0·1119 g, M = 223·0) with the same relation. What do you find?
Answer: A
2 × 143.2 × 0.1140 ÷ 0.1119 ≈ 291.77, and 291.77 - 70.8 ≈ 221.0, two units below the printed 223·0. Estimations I, III and IV reproduce their printed values, so either a weighing or the result of estimation II is misprinted in this edition, and this page alone cannot tell which. Another source settles it: the French text of the thesis (Recherches sur les substances radioactives, 1903) prints the chloride mass as 0,1148 g, and 2 × 143.2 × 0.1148 ÷ 0.1119 - 70.8 ≈ 223.0, so the misprint is the 0·1140 of this English edition. The error does not touch Curie's final value, which comes from the re-purified chloride. Choice B is what a reader who does not check would assume. Choice C mixes up the two tables. Choice D gives the value before the chlorine is subtracted, which is not an atomic weight.
Question 6 of 20 · Multiple Choice
The re-purified chloride gave 225·3, 225·8 and 224·0 (Curie's third table), and Curie reports the mean as 225. How well do these three values support "Ra = 225"?
Answer: B
The mean is (225.3 + 225.8 + 224.0) ÷ 3 ≈ 225.0, and the range, 225.8 - 224.0 = 1.8, is less than 1 percent of 225, so the method gives consistent results. Consistency is not the same as correctness: an error shared by every trial, such as a wrong value for chlorine or a trace of barium, would shift all three together. Choice A claims too much for repetition. Choices C and D ask for more agreement or more trials than such small, precious samples allowed, and ignore how close the values are.
Question 7 of 20 · Multiple Choice
Curie's result assumes radium is "bivalent" (RaCl₂; T3, paragraph 7). If radium formed RaCl₃ instead, the relation would become M + 106.2 = 3 × 143.2 × (mass of radium chloride) ÷ (mass of silver chloride). What would estimation I of the re-purified chloride give?
Answer: D
3 × 143.2 × 0.09192 ÷ 0.08890 ≈ 444.2, and 444.2 - 106.2 ≈ 338.0. The same weighings give a very different atomic weight under a different assumption, so the conclusion "Ra = 225" is only as strong as the evidence for bivalence. Choice A keeps the answer for RaCl₂, as if the assumption did not matter. Choice B scales 225.3 by 2/3, which is not how the relation works. Choice C forgets to subtract the three chlorine atoms.
Question 8 of 20 · Multiple Choice
How do the last two paragraphs of T3 bear on the assumption that radium is bivalent?
Answer: C
Paragraph 9 rests on chemistry: radium behaves like barium, an alkaline earth metal whose chloride is BaCl₂, so treating radium as bivalent is reasonable on evidence gathered apart from the weighing. Paragraph 10 places radium in the table "From its atomic weight," but that atomic weight was calculated by assuming bivalence, so it partly supports itself. Choice A misses the circularity. Choice B misses that valence is what places an element in a column. Choice D misreads paragraph 10: uranium and thorium are in the same row, not the same group.
Question 9 of 20 · Multiple Choice
Rutherford (T4, paragraph 1) says the atomic weights of the mixtures "were 146 and 175" before the final 225. How does his account compare with Curie's first table in T3?
Answer: A
Rutherford's 146 is Curie's 145·8 rounded, and his final 225 and his starting value "the same as that of barium" match T3. But 173·8 rounds to 174, not 175, so on that value the two sources disagree; Rutherford may have used an earlier report. A careful reader notes the difference and the source it points to. Choice B misreads "steadily increasing purity." Choice C ignores the 173·8. Choice D is false: both give 225.
Question 10 of 20 · Multiple Choice
What kind of evidence did Runge and Precht use to arrive at 258 (T4, paragraph 3)?
Answer: B
Rutherford writes that they found spectral series "analogous to those observed for calcium, barium, and strontium" and that "These series are connected with the atomic weights," so they calculated 258 "by these means." This is an independent method, which is why its disagreement matters: it is a genuine challenge, not a repeat. Choice A describes Curie's method. Choice C confuses activity with atomic weight. Choice D is Rutherford's reason for preferring Curie's value, not Runge and Precht's method.
Question 11 of 20 · Multiple Choice
Marshall Watts "deduced the value obtained by Mme Curie" from the spectrum, but Runge criticized his method (T4, paragraph 3). How much should Watts's result count as corroboration?
Answer: D
Corroboration counts only as far as the method behind it is sound. Runge's objection, that "the lines used for comparison in the different spectra were not homologous" (not true counterparts), attacks the method, so Watts's agreement is weak support until the objection is met. Choice A counts agreement without weighing method. Choice B is too strong: Runge and Precht's own challenge also comes from the spectrum. Choice C prefers newness over the reliability of the method.
Question 12 of 20 · Multiple Choice
A modern source gives 226.03 for the mass of radium-226, the isotope Curie isolated. About how far is each 1904 value from it, as a percentage of 226.03?
Answer: A
(226.03 - 225) ÷ 226.03 ≈ 0.0046, about 0.5 percent, and (258 - 226.03) ÷ 226.03 ≈ 0.141, about 14 percent. The later source corroborates Curie's chemical value and challenges the spectroscopic one, as Rutherford judged. Choice B reports the differences in atomic-weight units (1.03 and 31.97) as if they were percentages. Choice C divides the second difference by 258 instead of 226.03. Choice D swaps the two results.
Question 13 of 20 · Multiple Choice
T1, paragraph 4, says artificial chalcolite "is two and a-half times less active than uranium." In Curie's apparatus, where uranium gave a current of 2·3 (in units of 10⁻¹¹ ampere), what current would that be?
Answer: C
"Two and a-half times less active" means the activity is uranium's divided by 2.5: 2.3 ÷ 2.5 = 0.92. Natural chalcolite gave 5·2, about 5.7 times as much as the artificial crystals. Choice A multiplies uranium's current by 2.5. Choice B divides natural chalcolite's 5·2 by 2.5, which is not what the sentence compares. Choice D multiplies natural chalcolite's current by 2.5.
Question 14 of 20 · Multiple Choice
Why is Curie's artificial chalcolite (T1, paragraphs 3-4) a strong test of the idea behind her hypothesis?
Answer: D
The artificial crystals have the same chemical make-up as natural chalcolite but were made "starting with the pure products," so anything else in the ore is left out. Their activity was "perfectly normal ... given by its composition," so the extra activity of the natural mineral must come from something besides its uranium and its chemistry. That is a controlled comparison. Choice A is false: the crystals are active, only not unusually so. Choice B names polonium, which T1 does not mention. Choice C reverses the result.
Question 15 of 20 · Short Answer
Curie's hypothesis (T1, paragraph 5) ends: "I might hope to extract this substance from the ore by the ordinary methods of chemical analysis." What prediction does the hypothesis make, what result would have challenged it, and how does T3 show the prediction being tested?
Model answer: It predicts that chemical separation of the ore will concentrate the activity: some fractions will be far more active than the ore, and a pure enough fraction will show a substance with its own properties. The hypothesis would have been challenged if every fraction had stayed only as active as its uranium, or if the activity had spread evenly through all the products. T3 shows the prediction being met: the barium chloride from pitchblende became "230 times" and "600 times as active as uranium," then "about 3500 times as great as that of uranium," with concentration, and at the highest activities its atomic weight rose above barium's, to 225, a value no known element had. Rubric: full credit for the prediction, a result that would challenge it and quoted evidence from T3; partial credit for two of these.
Question 16 of 20 · Short Answer
Recompute estimation I of the re-purified chloride with today's values, Ag = 107.87 and Cl = 35.45 (so M + 70.9 = 2 × 143.32 × mass of chloride ÷ mass of silver chloride). How much does updating the constants change the result? What other cause of the remaining gap to 226.03 does T3 point to?
Model answer: 2 × 143.32 × 0.09192 ÷ 0.08890 ≈ 296.38, and 296.38 - 70.9 ≈ 225.5, up from 225.3, so the constants explain only about 0.15 of the gap of about 0.7 to 226.03, leaving about 0.55. T3 points to barium: even the purest chloride showed barium lines, "very faint," and Demarçay judged the traces "incapable of influencing the atomic weight to an appreciable extent." Barium is much lighter (137), so any barium left would pull M down, which is the direction of the gap; weighing errors with samples under 0·1 g are another possibility. Rubric: full credit for about 225.5, the size of the change, and a cause tied to T3; partial credit for the calculation alone.
Question 17 of 20 · Short Answer
Evaluate the conclusion "the atomic weight of radium is Ra = 225" (T3, paragraph 8). Use at least two other sources of information on this page to corroborate or challenge it, and give your verdict.
Model answer: The conclusion follows from careful data: a barium control that gave the right answer, three consistent determinations (224·0 to 225·8), and a trend of rising values as the samples grew purer. Two sources corroborate it. Rutherford (T4) reports the same final value and prefers it because "the number found by Mme Curie agrees with that required by the periodic system," and the modern mass of radium-226, 226.03, is within about 0.5 percent. One source challenges it: Runge and Precht's 258 from the spectrum, an independent method, though Rutherford gives reasons to prefer the chemical value and the modern value supports him. A limit is the assumption that radium is bivalent. Verdict: well supported for its time, and corroborated since. Rubric: full credit for two other sources used to corroborate or challenge, the bivalence limit and a verdict; partial credit for one source and a verdict.
Question 18 of 20 · Short Answer
Curie writes that some pitchblendes "are four times as active as metallic uranium" (T1, paragraph 2). Verify this against her table and Diagram 2, and evaluate how precisely she words the claim.
Model answer: The most active pitchblende, from Johanngeorgenstadt, gave 8·3 against uranium's 2·3, and 8.3 ÷ 2.3 ≈ 3.6, so "four times" rounds up; "between three and four times" would be closer. The other pitchblendes gave 7·0 and 6·5 (about 3.0 and 2.8 times), and the Cornwallis sample gave only 1·6, less than uranium. Curie's wording, "pitchblendes ... are found which are," claims only that some samples are this active, not all, which the table supports. Rubric: full credit for the ratio 3.6, the Cornwallis exception and an evaluation of "are found"; partial credit for the ratio alone.
Question 19 of 20 · Short Answer
Curie's evidence in T1 is a set of currents from minerals. Evaluate the data themselves: name one strength and one weakness of these data as evidence for the hypothesis, citing T1.
Model answer: Strength: every mineral was measured in the same apparatus against the same standard, metallic uranium, so the comparison is consistent, and the anomaly is large; several minerals gave more current than pure uranium, which should be impossible if activity came only from their uranium. Weakness: the table gives one reading per sample with no repeat, and T1 says nothing about how much of each sample was used or how it was prepared, so small differences, such as autunite's 2·7 against uranium's 2·3, are less secure than large ones. Rubric: full credit for one strength and one weakness, each tied to T1; partial credit for one.
Question 20 of 20 · Short Answer
Rutherford (T4, paragraph 3) advises accepting Curie's 225 "rather than the one deduced by Runge and Precht," because it "agrees with that required by the periodic system." Evaluate this reasoning. What kind of evidence is agreement with the periodic system, and what could have challenged it?
Model answer: It is evidence of consistency with an established theory: the periodic system had a place for an alkaline earth metal below barium, and a value near 225 fits that place while 258 fits it poorly. That is a reasonable ground for preferring one value in "the present state of our knowledge," as Rutherford carefully says, but it is not a direct measurement, and a theory can be wrong or incomplete. It would have been challenged by a second chemical determination far from 225, or by a spectral method that other physicists accepted as sound. Rutherford also weighs the methods: Curie's number is "the experimental number," while 258 is "deduced." Rubric: full credit for naming the reasoning as consistency with theory, a limit, and what could challenge it; partial credit for two of these.
0 of 20 answered · 0 correct
06
Frequently Asked Questions
10 Questions
What does RST.11-12.8 mean?
RST.11-12.8 asks students in grades 11-12 to evaluate a science or technical text part by part: its hypotheses, data, analysis and conclusions. Where the text gives enough numbers, they verify the data themselves, and they corroborate or challenge the conclusions by comparing them with other sources of information.
What does "verifying the data when possible" look like in class?
It means redoing the text's own numbers: recomputing a ratio, a mean or a result from the measurements given, and checking that units convert correctly. In this lesson students recompute Curie's atomic weights from her weighings and check whether each printed value follows from its masses.
How is RST.11-12.8 different from RST.9-10.8?
RST.9-10.8 asks how far the reasoning and evidence in one text support its claim or recommendation. RST.11-12.8 asks for a fuller evaluation of the hypotheses, data, analysis and conclusions, adds checking the data by calculation, and requires comparing the conclusions with other sources.
What counts as "other sources of information" for RST.11-12.8?
Anything independent of the text: another experiment on the same question, a different method, a reference table of accepted values, a later study or a review. A source that used a different method counts for more than one that repeated the same method, because it can catch errors the first method shares.
What is the difference between corroborating and verifying?
Verifying checks the text against itself: do its numbers follow from its own measurements? Corroborating checks the text against the world: do other sources reach the same conclusion? A study can pass the first check and fail the second, or the reverse.
Why teach RST.11-12.8 with Marie Curie's thesis?
Her thesis states a hypothesis, prints the raw weighings and tables behind her results, and explains her analysis, so students can check it themselves. A year later, Rutherford reported the same work and a competing value, which gives students a real conclusion to corroborate and challenge.
Do students need chemistry to evaluate Curie's data?
Only a little, and the lesson supplies it. Students use one relation, given in the questions, to turn two masses into an atomic weight, and they compare ratios of currents. The skill being assessed is evaluation: deciding what the numbers show, what they assume and what other sources say.
What mistakes do students often make with this standard?
They accept a conclusion because the arithmetic checks out, forgetting that correct numbers can still be over-interpreted; they treat several repeats of the same method as independent corroboration; and they ignore stated assumptions, such as Curie's assumption that radium is bivalent, on which the result depends.
How is RST.11-12.8 usually assessed?
Usually with a science or technical text that reports a study: students identify the hypothesis, check a calculation, judge whether the conclusion goes beyond the data, and compare it with a second source. Short written evaluations, like the homework on this page, show the reasoning best.
How does RST.11-12.8 connect to writing and to science courses?
It is the reading side of scientific argument. Students who can evaluate a study can write their own claims with evidence (WHST.11-12.1) and can synthesize several sources into one account (RST.11-12.9). In chemistry, physics and biology courses it is the everyday work of reading lab reports and published results critically.
07
Related Standards
5 standards
These standards connect to RST.11-12.8: prerequisites to review first, parallel standards at the same level, and next steps that build on it.
Before this lesson
RST.9-10.8Prerequisite
Assess how far a text's reasoning and evidence support its claim or recommendation