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HSN.VM.A.2Common CoreMathNumber and QuantityGrades 9-12

HSN.VM.A.2: Finding Vector Components from Initial and Terminal Points

In plain English: HSN.VM.A.2 is an advanced (+) Common Core number and quantity standard that asks students to find the components of a vector by subtracting the coordinates of its initial point from the coordinates of its terminal point. A vector from (x1, y1) to (x2, y2) has components ⟨x2 - x1, y2 - y1⟩, the horizontal and vertical change. It is usually taught in Precalculus.

(+) Find the components of a vector by subtracting the coordinates of an initial point from the coordinates of a terminal point.

Common Core State Standards for Mathematics · Domain: Vector and Matrix Quantities (VM) · Cluster: Represent and model with vector quantities.
Also written as HSN-VM.A.2 or N-VM.2 · Official standard

01

Lesson Plan

60 min

Overview

Students learn to write a vector in component form by subtracting coordinates: for a vector with initial point (x1, y1) and terminal point (x2, y2), the components are ⟨x2 - x1, y2 - y1⟩. The x-component is the horizontal change and the y-component is the vertical change as you travel from the tail of the arrow to its head. Students see that the order of subtraction sets the direction, that equal vectors in different places have the same components, and that the same rule works in three dimensions.

How vectors are written here. Bold letters such as v are vectors, and AB in bold is the vector that starts at A and ends at B. Components go inside angle brackets, as in ⟨4, 5⟩, so that a vector is not confused with the point (4, 5). On paper, students mark a vector with an arrow above the letter or letters.

Learning Objectives

By the end of this lesson, students will be able to:

  • Find the components of a vector by subtracting the coordinates of its initial point from the coordinates of its terminal point
  • Interpret the sign and size of each component as a horizontal or vertical change
  • Explain why reversing the initial and terminal points gives the opposite vector, and why equal vectors have equal components
  • Work backward from components and one endpoint to the other endpoint, in two and three dimensions

Prior Knowledge Required

Students should already be comfortable with:

  • Plotting points in all four quadrants and finding horizontal and vertical distances 6.NS.C.8
  • Subtracting signed numbers, including subtracting a negative 7.NS.A.1
  • Vectors as directed line segments with an initial and a terminal point HSN.VM.A.1

Lesson Procedure

60-60 minutes of class time across 5 phases.

  1. Warm-Up10 minutes

    Draw a coordinate grid on the board and label it as the floor of a warehouse, 1 unit per meter. Pose the question below and have students answer on mini whiteboards.

    Warm-Up Prompt

    "A delivery robot rolls from (2, 3) to (7, 1). How many meters did it move left or right, and how many up or down? Then it rolls back from (7, 1) to (2, 3). What changes?"

    Students usually count squares and say 5 right and 2 down, then 5 left and 2 up. Ask how they could get those numbers without the grid. Guide them to subtract: 7 - 2 = 5 and 1 - 3 = -2. Record the signs: right and up are positive, left and down are negative. The return trip gives 2 - 7 = -5 and 3 - 1 = 2. Tell students that these pairs of changes are the components of the robot's displacement vector.

  2. Direct Instruction20 minutes

    The rule. A vector drawn from initial point (x1, y1) to terminal point (x2, y2) has components ⟨x2 - x1, y2 - y1⟩. A short way to say it: head minus tail. Use Diagram 1 to show that the two components are the legs of the right triangle under the arrow, and that sliding the arrow so its tail sits at the origin puts its head exactly at the point whose coordinates are the components.

    1. Name the points: decide which point is the initial point (tail) and which is the terminal point (head). The wording "from ... to ..." tells you.
    2. Subtract x-coordinates: terminal x minus initial x gives the x-component.
    3. Subtract y-coordinates: terminal y minus initial y gives the y-component. Put parentheses around negative coordinates before subtracting.
    4. Write and read the result: write ⟨a, b⟩ and describe it: a positive a means right, negative means left; a positive b means up, negative means down.
    5. Check with a sketch: the arrow from the tail should move the way the signs say.

    Stress three consequences. Reversing the order gives the opposite vector: DC = -CD (Diagram 2). Two arrows in different places with the same components are equal vectors. The rule works the same way in three dimensions, one subtraction per coordinate.

    • Basic subtraction

      Find the components of the vector from A(2, -1) to B(6, 4).

      Equation: AB = ⟨6 - 2, 4 - (-1)⟩ = ⟨4, 5⟩

    • Negative components

      Find the components of the vector from C(3, 5) to D(-1, 2).

      Equation: CD = ⟨-1 - 3, 2 - 5⟩ = ⟨-4, -3⟩: 4 left and 3 down

    • Reversing the order

      Now find the vector from D(-1, 2) to C(3, 5) and compare.

      Equation: DC = ⟨3 - (-1), 5 - 2⟩ = ⟨4, 3⟩ = -CD

    • Working backward to the terminal point

      A vector with components ⟨-2, 7⟩ has initial point (5, -3). Where is its terminal point?

      Equation: x2 - 5 = -2 and y2 - (-3) = 7, so the terminal point is (3, 4)

    • Three dimensions

      A drone moves from (1, 2, 0) to (4, 6, 5), in meters east, north and up. Find its displacement.

      Equation: ⟨4 - 1, 6 - 2, 5 - 0⟩ = ⟨3, 4, 5⟩: 3 m east, 4 m north, 5 m up

  3. Guided Practice10 minutes

    Pairs complete the table. One partner computes and the other checks with a sketch on graph paper; they swap roles for each row.

    Guided practice vectors
    FromToComponentsReads as
    E(-2, -3)F(1, 1)⟨3, 4⟩3 right, 4 up
    G(0, 6)H(-5, 6)⟨-5, 0⟩5 left, no vertical change
    J(4, -2)K(4, -9)⟨0, -7⟩straight down 7
    M(-1.5, 2)N(2.5, -0.5)⟨4, -2.5⟩4 right, 2.5 down

    Listen for three errors: subtracting initial minus terminal, dropping the sign when subtracting a negative (writing -3 - -2 as -5), and putting the y-change first. Ask what a zero component means for the direction of the arrow.

  4. Independent Practice15 minutes

    A trail map uses coordinates in kilometers east and north of a parking lot. Students find the displacement for each leg of a hike, with the components and a sentence such as "5 km east and 3 km north":

    • Trailhead (1, -2) to waterfall (6, 1): ⟨5, 3⟩
    • Waterfall (6, 1) to summit (3, 9): ⟨-3, 8⟩
    • Summit (3, 9) back to the trailhead (1, -2): ⟨-2, -11⟩
    • A second group starts at the ranger station (-4, 0) and hikes a leg equal to the first leg. Where do they end? (1, 3)

    Early finishers write the vector from the trailhead to the summit and explain why it is not the same as the first leg.

  5. Closure5 minutes

    Exit ticket: (1) Find the components of the vector from P(-4, 2) to Q(1, -6). (Answer: ⟨5, -8⟩.) (2) A classmate got ⟨-5, 8⟩ for the same vector. What did the classmate do? (3) A vector with components ⟨3, -1⟩ ends at the origin. Where does it start? (Answer: (-3, 1).)

Differentiation Strategies

For Struggling Students

  • Give a template: ⟨(head x) - (tail x), (head y) - (tail y)⟩, with boxes for each coordinate and parentheses printed around every box
  • Have students count squares on a grid first and then confirm the count by subtraction, so the two methods agree
  • Color-code: tail coordinates in one color, head coordinates in another, and the color order never changes

For Advanced Students

  • Prove with variables that the components of the vector from Q to P are the opposites of those from P to Q
  • Given three vertices of a parallelogram, find every possible fourth vertex by using equal vectors
  • Find the components of a displacement in three dimensions from GPS-style coordinates, then describe it in words

Assessment Guidance

What to Look For

Check that students always subtract in the same order, terminal minus initial, and can say why that order matters. Look for correct handling of negative coordinates, especially y2 - (-3). Ask students to read their components in words ("4 left, 3 down") and to match them with a sketch: a student who can do that is less likely to reverse the order. When students work backward, they should add the components to the initial point, and subtract them from the terminal point.

02

Classroom Activities

3 Activities

1

Component Treasure Hunt

20 minPairs

Pairs follow a chain of six clue cards across a coordinate grid. Each card gives a vector in component form, and the terminal point of each move is the initial point of the next. At the end, pairs check each leg in reverse by subtraction, so every leg is tested with the standard's rule.

Clue Cards (start at the origin)

  • Card 1: ⟨3, 2⟩; Card 2: ⟨-5, 1⟩; Card 3: ⟨4, -6⟩
  • Card 4: ⟨-1, 4⟩; Card 5: ⟨6, 3⟩; Card 6: ⟨-7, -4⟩
  • Answer key for the teacher: (3, 2), (-2, 3), (2, -3), (1, 1), (7, 4), and Card 6 returns to (0, 0)

Procedure

  • Partner A reads a card and plots the next point; Partner B draws the arrow and labels its tail and head
  • After all six moves, pairs list the seven points in order and find the components of each leg by subtracting coordinates, terminal minus initial
  • Every recomputed leg must match its card; a mismatch means a plotting or subtraction error to find and fix

Discussion Questions

  • Why did the hunt end at the starting point?
  • If Card 4 were read backward, from head to tail, what components would you get?

Modification for Distance Learning

Share the clue cards in a slide deck and have pairs plot on an online graphing tool, then paste a screenshot of their path and the subtraction table.

2

Head Minus Tail Error Hunt

15 minGroups of 3

Groups review six worked answers from an imaginary student. Some are right and some have one error. For each one, the group decides whether it is correct, names the error, and fixes it.

The Six Worked Answers

  • From P(2, 7) to Q(5, 1): student wrote ⟨-3, 6⟩ (order reversed; correct: ⟨3, -6⟩)
  • From R(-3, 4) to S(2, 9): student wrote ⟨-1, 5⟩ (added -3 instead of subtracting it; correct: ⟨5, 5⟩)
  • From U(1, -6) to V(4, -2): student wrote ⟨3, -8⟩ (sign error in -2 - (-6); correct: ⟨3, 4⟩)
  • From W(0, 3) to Z(-4, 0): student wrote ⟨-3, -4⟩ (components swapped; correct: ⟨-4, -3⟩)
  • From G(6, -1) to H(-2, -5): student wrote ⟨-8, -4⟩ (correct)
  • From K(-7, -2) to L(-1, 3): student wrote ⟨-8, 1⟩ (added coordinates; correct: ⟨6, 5⟩)

Procedure

  • Each student checks two answers alone, then explains them to the group
  • The group agrees on a verdict and writes the error type in a few words
  • Groups make a class poster of error types with one example each

Challenge Variation

Each group writes two new worked answers, one correct and one with a hidden error, and trades them with another group.

3

Radar Screen Displacements

20 minPairs

A printed radar screen shows four aircraft, with positions in kilometers east and north of a control tower, at 2:00 and at 2:01. Pairs find each plane's one-minute displacement vector and compare the vectors.

Radar Data

  • Plane A: (-12, 8) at 2:00, (-4, 2) at 2:01
  • Plane B: (5, -10) at 2:00, (13, -16) at 2:01
  • Plane C: (10, 10) at 2:00, (2, 16) at 2:01
  • Plane D: (-6, -3) at 2:00, (-6, 7) at 2:01

Procedure

  • Find each displacement as the later position minus the earlier one
  • Identify two planes whose displacements are equal vectors even though the planes are far apart
  • Identify two planes flying in exactly opposite directions
  • Describe Plane D's motion in words, and explain what its zero x-component means

Discussion Questions

  • Why must we subtract the 2:00 position from the 2:01 position, and not the other way?
  • Plane A moves 10 km each minute. Is that a realistic speed for a jet in kilometers per hour?

03

Diagrams & Visual Aids

2 diagrams

Diagram 1: Components as Horizontal and Vertical Change

-1 1 2 3 4 5 6 7 8 -2 -1 1 2 3 4 5 6 A(2, -1) B(6, 4) 6 - 2 = 4 4 - (-1) = 5 (4, 5) v Terminal minus initial x: 6 - 2 = 4 y: 4 - (-1) = 5 v = ⟨4, 5⟩ Dashed gray arrow: the same vector drawn from the origin. Its terminal point is (4, 5), the component form.
Vector v runs from A(2, -1) to B(6, 4). The dashed legs show the horizontal change 6 - 2 = 4 and the vertical change 4 - (-1) = 5, so v = ⟨4, 5⟩. The gray dashed arrow is the same vector with its initial point at the origin; its terminal point is (4, 5). Drawn to scale, 1 unit per square.

Diagram 2: Reversing the Order Reverses the Vector

-2 -1 1 2 3 4 1 2 3 4 5 6 C(3, 5) D(-1, 2) From C to D CD = ⟨-1 - 3, 2 - 5⟩ = ⟨-4, -3⟩ -2 -1 1 2 3 4 1 2 3 4 5 6 C(3, 5) D(-1, 2) From D to C DC = ⟨3 - (-1), 5 - 2⟩ = ⟨4, 3⟩
The same two points give two different vectors. From C to D the components are ⟨-4, -3⟩ (left and down). From D to C they are ⟨4, 3⟩ (right and up), so DC = -CD. Both grids are drawn to scale.

04

Homework Assignment

~30 min

HSN.VM.A.2 Homework: Components from Initial and Terminal Points

Directions: Show each subtraction, with parentheses around negative coordinates. Write components in angle brackets, ⟨a, b⟩, and describe each vector in words (for example, "2 left and 5 up"). Sketch at least three of your vectors on graph paper.

Part 1: Components from Two Points (Problems 1-2)

  1. Find the components of the vector from the first point to the second: (a) A(1, 4) to B(7, 9) (b) C(-2, 3) to D(-8, -1) (c) E(5, -4) to F(5, 2) (d) G(-3.5, 0) to H(1, -2.5)
  2. Let M = (-1, -4) and N = (3, 2). Find the components of MN and of NM. How are the two answers related, and why?

Part 2: Working Backward and Equal Vectors (Problems 3-4)

  1. (a) A vector with components ⟨-6, 5⟩ has initial point (2, -3). Find its terminal point. (b) A vector with components ⟨4, -9⟩ has terminal point (1, 1). Find its initial point. Check both answers by subtracting.
  2. The points P(1, 1), Q(5, 2), R(7, 6) and S(3, 5) are the vertices of quadrilateral PQRS. Find the components of PQ, SR, QR and PS. Which pairs are equal vectors? What does that tell you about the shape?

Part 3: Components in Context (Problems 5-6)

  1. A drone takes off from a landing pad at (4, -2, 0) and hovers at (-3, 10, 25), with coordinates in meters east, north and up from a fixed marker. Find the components of the drone's displacement and explain what each component means.
  2. In a video game, a character jumps from (-15, 40) to (25, 10) on the map. Find the components of the jump. A second character standing at (60, -5) makes a jump with the same vector. Where does the second character land?

Rubric

CriterionFull Credit (2 pts)Partial Credit (1 pt)No Credit (0 pts)
Subtraction OrderTerminal minus initial every time, with work shownOrder right but one sign errorOrder reversed or coordinates added
Working BackwardBoth missing points found and checkedOne point correct or no checkNeither point correct
InterpretationEvery vector described in words and matched to a sketchDescriptions given for some vectorsNo descriptions or sketches
ReasoningClear explanations for opposite and equal vectorsCorrect conclusion with a weak reasonNo explanation

05

Quiz: 20 Questions

Interactive, with answers

Instructions

Answer each question, then read the explanation. Components are written in angle brackets, and bold letters are vectors. Your score updates as you go, and Reset quiz clears all answers for another attempt.

Multiple choice: pick an option to check it. Short answer: write your answer, then reveal the model answer.

0 of 20 answered · 0 correct

  1. Question 1 of 20 · Multiple Choice

    What are the components of the vector from (3, 1) to (8, 7)?

  2. Question 2 of 20 · Multiple Choice

    What are the components of the vector from (-2, 5) to (4, -1)?

  3. Question 3 of 20 · Multiple Choice

    A vector goes from P(x1, y1) to Q(x2, y2). Which expression gives the y-component of the vector from Q back to P?

  4. Question 4 of 20 · Multiple Choice

    What are the components of the vector from (-4, -3) to (-9, 2)?

  5. Question 5 of 20 · Multiple Choice

    A vector with components ⟨-3, 8⟩ has initial point (6, -2). What is its terminal point?

  6. Question 6 of 20 · Multiple Choice

    A vector with components ⟨2, -4⟩ has terminal point (0, 5). What is its initial point?

  7. Question 7 of 20 · Multiple Choice

    A vector from R(1, 1) to S has components ⟨0, -4⟩. Which describes the vector?

  8. Question 8 of 20 · Multiple Choice

    Which vector is equal to the vector from (0, 0) to (-3, 4)?

  9. Question 9 of 20 · Multiple Choice

    The vector from A to B has components ⟨7, -2⟩. What are the components of the vector from B to A?

  10. Question 10 of 20 · Multiple Choice

    A drone flies from (2, -1, 4) to (5, 3, 0), in meters. What are the components of its displacement?

  11. Question 11 of 20 · Multiple Choice

    A student finds the vector from (-3, 2) to (5, 6) and writes ⟨2, 4⟩. What went wrong?

  12. Question 12 of 20 · Multiple Choice

    A ship moves from (12, -8) to (-3, -8), in kilometers east and north of a port. What are the components of its displacement?

  13. Question 13 of 20 · Multiple Choice

    The vector v = ⟨4, -3⟩ is drawn with its initial point at the origin. What is its terminal point?

  14. Question 14 of 20 · Multiple Choice

    Points A(0, 0), B(5, 1) and C(9, 3) are three vertices of parallelogram ABCD. Find D so that AD = BC.

  15. Question 15 of 20 · Short Answer

    Find the components of the vector from J(-7, 3) to K(-2, -9), and describe the vector in words.

  16. Question 16 of 20 · Short Answer

    A vector with components ⟨-5, 9⟩ ends at (-1, 4). Find its initial point, and check your answer.

  17. Question 17 of 20 · Short Answer

    Let P = (a, b) and Q = (c, d). Use the subtraction rule to show that the components of the vector from Q to P are the opposites of the components of the vector from P to Q.

  18. Question 18 of 20 · Short Answer

    A hiker's GPS gives her position in kilometers east and north of a ranger station: (-1.2, 3.5) at 9:00 and (2.6, 0.9) at 10:00. Find the components of her displacement and describe it in words.

  19. Question 19 of 20 · Short Answer

    Is the vector from (1, -2) to (4, 3) equal to the vector from (-5, 0) to (-2, 5)? Justify your answer with components.

  20. Question 20 of 20 · Short Answer

    The vector from (k, 2) to (7, -3) has x-component 10. Find k and the y-component.

0 of 20 answered · 0 correct

06

Frequently Asked Questions

10 Questions

What does HSN.VM.A.2 mean?

HSN.VM.A.2 asks students to find the components of a vector from two points: subtract the coordinates of the initial point from the coordinates of the terminal point. For a vector from (1, 2) to (6, 0), the components are ⟨6 - 1, 0 - 2⟩ = ⟨5, -2⟩. The (+) in front of the standard marks it as advanced content for students headed to courses such as Precalculus or Calculus.

Is HSN.VM.A.2 part of Algebra 2 or Precalculus?

It is usually part of Precalculus, together with the other vector standards. Physics courses often teach the same skill for displacement, sometimes earlier. The subtraction itself only needs middle school integer skills, so it can be introduced whenever vectors are.

Why subtract the initial point from the terminal point and not the other way around?

Because a vector describes the change from where it starts to where it ends. "Ending position minus starting position" is the same idea as change in temperature or change in balance. Subtracting the other way describes the trip backward, which is the opposite vector.

What does a negative component mean?

A negative x-component means the vector points left (or west on a map), and a negative y-component means it points down (or south). A component of 0 means no change in that direction, so the arrow is horizontal or vertical. The sign carries direction; the size of the component carries the amount of change.

What notation is used for component form?

This page uses angle brackets, ⟨a, b⟩, so a vector is not confused with the point (a, b). Textbooks also use (a, b), a column with a on top of b, or ai + bj, where i and j are the unit vectors along the axes. All of these mean the same vector. Students should recognize each form.

What is the difference between a point and a vector in component form?

A point is a location. A vector is a change, with no fixed location. The vector ⟨2, 3⟩ can start anywhere; wherever it starts, it ends 2 units to the right and 3 units up. Only when the vector starts at the origin do its components match the coordinates of its terminal point.

Do equal vectors always have the same components?

Yes. Two vectors are equal when they have the same magnitude and direction, and that happens exactly when their components match. This is why component form is so useful: to test whether two arrows in different places are equal, subtract and compare, with no measuring.

Does this method work in three dimensions?

Yes. Subtract each coordinate the same way. For a vector from (x1, y1, z1) to (x2, y2, z2), the components are ⟨x2 - x1, y2 - y1, z2 - z1⟩. The standard does not limit students to the plane, and three-dimensional examples such as drone flights show why the rule matters.

What mistakes do students make when finding components?

Common ones are subtracting in the wrong order, mishandling a negative coordinate (writing 2 - (-3) as -1), adding coordinates instead of subtracting, and writing the y-change first. When working backward, students often subtract the components when they should add them. A quick sketch catches many of these errors, because the arrow must move the way the signs say.

How does HSN.VM.A.2 connect to later vector standards?

Component form is the tool for almost everything that follows. The magnitude of ⟨a, b⟩ is √(a² + b²), the distance formula from geometry. HSN.VM.A.3 uses components to solve velocity and force problems, and HSN.VM.B.4 and HSN.VM.B.5 add vectors and multiply them by scalars one component at a time.