HSF.LE.A.1: Distinguishing Linear and Exponential Models
In plain English: HSF.LE.A.1 is the Common Core functions standard that asks students to tell apart situations modeled by linear functions and situations modeled by exponential functions. Students prove that linear functions change by equal differences over equal intervals while exponential functions change by equal factors, and they recognize constant-rate and constant-percent-rate situations. It is usually taught in Algebra I.
Distinguish between situations that can be modeled with linear functions and with exponential functions.
a.Prove that linear functions grow by equal differences over equal intervals, and that exponential functions grow by equal factors over equal intervals.
b.Recognize situations in which one quantity changes at a constant rate per unit interval relative to another.
c.Recognize situations in which a quantity grows or decays by a constant percent rate per unit interval relative to another.
Common Core State Standards for Mathematics · Domain: Linear, Quadratic, and Exponential Models (LE) · Cluster: Construct and compare linear, quadratic, and exponential models and solve problems Also written as HSF-LE.A.1 or F-LE.1 · Official standard
Students learn to tell whether a situation calls for a linear or an exponential model. The lesson starts from the defining patterns: over equal intervals, a linear function always changes by the same difference and an exponential function always changes by the same factor. Students prove both facts algebraically for any interval, not only for the rows of one table.
Students then apply the patterns to words and tables. A constant rate per unit interval, such as gallons per minute, points to a linear function; a constant percent rate per unit interval, such as 2.5% per year, points to an exponential function. Tables with unequal input steps and phrases such as "percentage points" give practice at reading situations carefully.
Learning Objectives
By the end of this lesson, students will be able to:
Prove that a linear function f(x) = mx + b changes by the same difference mh over every interval of length h
Prove that an exponential function g(x) = a · bˣ changes by the same factor bʰ over every interval of length h
Recognize situations in which a quantity changes at a constant rate per unit interval and model them with linear functions
Recognize situations in which a quantity grows or decays by a constant percent rate per unit interval and model them with exponential functions
Decide from a table, including one with unequal input steps, whether the data are linear, exponential or neither
Prior Knowledge Required
Students should already be comfortable with:
Linear functions, slope as a rate of change and the form y = mx + b 8.F.A.3
Constructing a linear function from a description or a table 8.F.B.4
Properties of integer exponents, such as bˣ⁺ʰ = bˣ · bʰ 8.EE.A.1
Converting percents to decimals and finding a percent of a quantity 7.RP.A.3
Post the two situations below and give students three minutes to build both tables before any discussion.
Warm-Up Prompt
"A plant is 4 cm tall and grows 2 cm each week. A patch of mold covers 4 cm² and its area doubles each week. Make a table of each quantity for weeks 0 to 4. How does each one change from one week to the next?"
Record the tables: the plant is 4, 6, 8, 10, 12 cm and the mold is 4, 8, 16, 32, 64 cm². Ask students to write the change under each pair of columns. The plant always adds 2; the mold adds 4, 8, 16 and 32, so its additions are not equal, but it is always multiplied by 2. Name the two patterns, "equal differences" and "equal factors," and tell students that the lesson will prove these patterns always hold for linear and exponential functions.
Direct Instruction20 minutes
Part 1: Prove the two growth patterns (standard a). A proof has to work for every interval of a given length, not only for the intervals in one table. Write the two general functions on the board, f(x) = mx + b and g(x) = a · bx with a ≠ 0, b > 0 and b ≠ 1, and walk through these steps:
Pick an arbitrary interval: from x to x + h, where h > 0 is the interval length and x can be any input.
Linear case, subtract: f(x + h) - f(x) = m(x + h) + b - (mx + b) = mh. The x cancels, so every interval of length h has the same difference mh.
Exponential case, divide: g(x + h) ÷ g(x) = a · bx + h ÷ (a · bx) = bh. The x cancels, so every interval of length h has the same factor bh.
Read the result: for h = 1 the difference is the slope m and the factor is the base b. Equal differences mean a linear function; equal factors mean an exponential function.
Work Examples 1 and 2 as numerical versions of the proof. Then use Diagram 1: the linear staircase has equal rises, and the exponential staircase has rises that grow while the ratio stays 2.
Part 2: Recognize the situation (standards b and c). Ask of every situation: "Does the same amount get added or subtracted in each unit of time, or does the quantity get multiplied by the same factor?" A constant rate per unit (gallons per minute, dollars per month) signals a linear model. A constant percent rate per unit (2.5% per year, 15% per year) signals an exponential model with factor 1 + r for growth or 1 - r for decay.
Proof: equal differences
For f(x) = 4x + 7, compare the outputs at the ends of any interval of length 3, from x to x + 3.
Equation: f(x + 3) - f(x) = (4x + 19) - (4x + 7) = 12 for every x
Proof: equal factors
For g(x) = 5 · 2ˣ, compare the outputs at the ends of any interval of length 3.
Equation: g(x + 3) ÷ g(x) = (5 · 2ˣ · 2³) ÷ (5 · 2ˣ) = 8 for every x
Constant rate (linear)
A 500-gallon tank drains at 12 gallons per minute. The same amount leaves in every minute.
Equation: V = 500 - 12t, a change of -12 gallons per minute; empty after 41⅔ minutes
Constant percent rate, growth (exponential)
A town of 8,000 people grows by 2.5% per year. Each year the population is multiplied by 1.025.
Equation: P = 8000(1.025)ᵗ, so P = 8,200 after 1 year
Constant percent rate, decay (exponential)
A car bought for $24,000 loses 15% of its value each year, so 85% remains after every year.
Equation: V = 24000(0.85)ᵗ, so V = $20,400 after 1 year
After Example 5, use Diagram 2 to compare two decreasing quantities that start at 200: one loses 25 each hour, the other loses 20% each hour. The linear one reaches 0 after 8 hours; the exponential one loses less and less each hour and never reaches 0.
Guided Practice15 minutes
Pairs classify five tables. For each one they write the differences and the ratios of consecutive outputs, then decide: linear, exponential or neither.
Table A: x = 0, 1, 2, 3, 4 and y = 3, 7, 11, 15, 19 (linear: difference 4 per unit)
Table B: x = 0, 1, 2, 3, 4 and y = 2, 6, 18, 54, 162 (exponential: factor 3 per unit)
Table C: x = 0, 1, 2, 3, 4 and y = 1, 2, 4, 7, 11 (neither: differences 1, 2, 3, 4 and ratios 2, 2, 1.75, about 1.57)
Table D: x = 0, 2, 4, 6 and y = 80, 40, 20, 10 (exponential: factor 1/2 over every 2 units)
Table E: x = 0, 1, 3, 4 and y = 5, 8, 14, 17 (linear: the inputs skip 2, but the change is 3 per unit on every interval)
Table E is the trap: the raw differences are 3, 6 and 3, but the intervals are not equal. Divide each difference by the length of its interval before comparing.
Independent Practice15 minutes
Students decide whether each situation is linear or exponential, name the constant rate or the constant percent rate, and write a function.
A gym charges a $25 sign-up fee plus $30 per month (linear: C = 25 + 30m)
A bacteria culture of 500 cells doubles every 20 minutes (exponential: factor 2 per 20 minutes)
A 400 mg dose of a medicine leaves the body at 18% per hour (exponential decay: A = 400(0.82)t)
A 24 cm candle burns down 1.5 cm per hour (linear: h = 24 - 1.5t)
$1,500 in a savings account earns 4% interest compounded yearly (exponential: B = 1500(1.04)t)
A phone battery at 100% drops 8 percentage points per hour of video (linear: P = 100 - 8t, because the same 8 points leave every hour)
The last item is a deliberate check: "percentage points" of a fixed full charge is a constant amount, not a constant percent of what is left.
Closure5-10 minutes
Exit ticket: (1) A quantity increases by 6 units every 2 hours. Linear or exponential? (Linear: equal differences of 6 over equal 2-hour intervals, a rate of 3 per hour.) (2) A quantity increases by 6% every 2 hours. Linear or exponential? (Exponential: factor 1.06 over every 2-hour interval.) (3) Show that for g(x) = a · bx, the ratio g(x + 1) ÷ g(x) does not depend on x. (It equals b.)
Differentiation Strategies
For Struggling Students
Give a two-row template under each table: one row for "subtract" (differences) and one for "divide" (ratios), so students always test both patterns
Start with situations that name the change explicitly ("adds 30 dollars each month", "is multiplied by 1.04 each year") before phrases like "4% interest"
Have students compute two or three values of each situation before classifying it, so the pattern is visible in numbers first
For Advanced Students
Ask students to prove the converse for whole-number inputs: if a sequence has equal ratios between consecutive terms, then it has the form a · bⁿ
Ask why a constant percent rate of 10% per year is not the same as 20% every 2 years, and find the exact 2-year factor (1.21)
Ask students to explain why an exponential model with 0 < b < 1 never reaches 0, while a decreasing linear model always crosses 0
Assessment Guidance
What to Look For
Listen for proofs that start from an arbitrary interval from x to x + h, not from two specific rows of a table: standard a asks students to prove, not only to observe. When students classify a table, check that they compare changes over intervals of the same length. In word problems, look for a clear reason tied to the wording: "the same number of gallons leaves every minute" or "the value is multiplied by 0.85 every year." A student who says "it goes up fast, so it is exponential" needs to be pushed back to differences and factors.
02
Classroom Activities
3 Activities
1
Stack It or Fold It
15 minPairs
Students measure two ways a pile of paper can get thicker: by adding one sheet at a time or by folding the pile in half. The two tables show equal differences and equal factors side by side.
Procedure
Each pair gets several sheets of printer paper. Take 0.1 mm as the thickness of one sheet (a typical value)
Stack: start with one sheet (step 0) and add one sheet at each step. Record the thickness for steps 0 to 6: 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7 mm
Fold: start with one sheet and fold the pile in half at each step. Record the thickness for steps 0 to 6: 0.1, 0.2, 0.4, 0.8, 1.6, 3.2, 6.4 mm
Under each table, write the differences and the ratios between consecutive steps, then label each table linear or exponential
Discussion Questions
Which table has a constant rate per step, and what is it? (Stack: 0.1 mm per step.)
Which table has a constant percent rate per step? (Fold: the thickness grows 100% per step, a factor of 2.)
Most pairs cannot fold a sheet more than 6 or 7 times. Use the table to explain why.
Modification for Distance Learning
Students fold a sheet at home and report how many folds they managed. The class builds both tables in a shared spreadsheet, with one column for differences and one for ratios.
2
Situation Sort
20 minGroups of 3-4
Groups sort 12 situation cards into four piles: linear increasing, linear decreasing, exponential growth and exponential decay. For each card they must underline the words that decide the pile.
The 12 Cards
A hiker descending a trail loses 300 meters of elevation per hour (linear decreasing)
A concert venue sells 250 tickets each day (linear increasing)
A new social media account gains 9% more followers each week (exponential growth)
The temperature difference between hot cocoa and the room shrinks by 10% each minute (exponential decay)
A rental car costs a $30 fee plus $45 per day (linear increasing)
A radioactive isotope loses half its mass every 8 days (exponential decay)
A $2,000 deposit earns 4.5% interest compounded yearly (exponential growth)
A printer tray holds 500 sheets and the printer uses 20 sheets per minute (linear decreasing)
A virus sample in a lab triples every 6 hours (exponential growth)
A basketball bounces back to 70% of its previous height on each bounce (exponential decay)
A worker earns $17.50 per hour (linear increasing)
Ice on a pond thickens by 0.4 cm per day during a cold spell (linear increasing)
Procedure
Groups cut out the cards and place each one in a pile, underlining the deciding words
Check against the key: 4 linear increasing (2, 5, 11, 12), 2 linear decreasing (1, 8), 3 exponential growth (3, 7, 9), 3 exponential decay (4, 6, 10)
For two cards of their choice, groups write the function and a three-row table
Challenge Variation
Groups rewrite three cards so that each one moves to a different pile, changing as few words as possible. For example, "sells 250 tickets each day" becomes "sells 5% more tickets each day."
3
Prove It Two Ways
20 minPairs
Students write the two proofs from standard a in their own words, then test them on specific functions over intervals of length 2. The goal is to see why a table can suggest a pattern but only algebra proves it for every interval.
Procedure
Partner A proves that f(x) = mx + b changes by mh over any interval from x to x + h. Partner B proves that g(x) = a · bx changes by the factor bh. Partners swap and check each other's steps
Test the proofs with h = 2: for f(x) = -3x + 10, the outputs at x = 0, 2, 4, 6 are 10, 4, -2, -8, a difference of -6 = -3 · 2 each time
For g(x) = 96(1/2)x, the outputs at x = 0, 2, 4, 6 are 96, 24, 6, 1.5, a factor of 1/4 = (1/2)2 each time
Pairs write one sentence explaining why the x cancels in each proof and what that means
Discussion Questions
Why is checking three rows of a table not a proof?
In the linear proof you subtract; in the exponential proof you divide. Why does each operation fit its function?
For g, what happens to the differences over intervals of length 2? (They shrink: -72, -18, -4.5.) Does that contradict the proof?
03
Diagrams & Visual Aids
2 diagrams
Diagram 1: Equal Differences Versus Equal Factors
Both graphs are drawn to scale for x = 0 to 4. On the line y = 3x + 2, every step of 1 unit to the right rises by the same amount, 3. On y = 2 · 2x, the rises grow (2, 4, 8, 16), but every step multiplies the output by the same factor, 2. Subtracting tests for linear; dividing tests for exponential.
Diagram 2: Losing a Constant Amount Versus a Constant Percent
Two quantities start at 200. Quantity A decreases at a constant rate of 25 per hour and reaches 0 at t = 8. Quantity B decreases by a constant percent rate of 20% per hour, so it is multiplied by 0.8 each hour: it loses 40 in the first hour but only about 10.5 between hours 6 and 7, and it never reaches 0. Points are plotted to scale at whole hours.
04
Homework Assignment
~30 min
HSF.LE.A.1 Homework: Linear or Exponential?
Directions: Show all work. When you classify a table, write the differences or the ratios you used, and adjust for intervals of different lengths. When you classify a situation, quote the words that decide it.
Part 1: Proving the Patterns (Problems 1-2)
Let f(x) = -2.5x + 40. (a) Find f(0), f(4), f(10) and f(14), and show that f changes by the same amount on the intervals from 0 to 4 and from 10 to 14. (b) Prove that f changes by this same amount over every interval of length 4, from x to x + 4.
Let g(x) = 81(1/3)x. (a) Prove that over every interval of length 2, from x to x + 2, the output is multiplied by the same factor, and find that factor. (b) Compute g(0), g(1), g(2) and g(3), and show that the differences g(2) - g(0) and g(3) - g(1) are not equal. Explain why this does not contradict part (a).
Part 2: Reading Tables (Problems 3-4)
Classify each table as linear, exponential or neither, and give the constant difference or factor per unit when there is one. Table P: x = 0, 1, 2, 3, 4 and y = 12, 18, 27, 40.5, 60.75. Table Q: x = 1, 2, 3, 4, 5 and y = 50, 43, 36, 29, 22. Table R: x = 0, 1, 2, 3, 4 and y = 2, 3, 6, 11, 18.
A table shows x = 0, 2, 5, 6, 10 and y = 7, 13, 22, 25, 37. A classmate says, "The differences are 6, 9, 3 and 12, so the data are not linear." Explain the error, decide whether the data are linear, and if they are, write the function.
Part 3: Situations (Problems 5-6)
Decide whether each situation is linear or exponential, state the constant rate or the constant percent rate, and write a function. (a) A streaming service has 1,200 subscribers and gains 150 new subscribers each month. (b) Algae cover 30 m² of a lake, and the covered area grows by 12% each day. (c) A snowbank 90 cm deep melts 4 cm each day. (d) A population of 640 rare birds falls by 5% each year.
A city bike-share program had 2,000 rides in its first month. Plan 1 predicts 300 more rides each month; Plan 2 predicts 12% more rides each month. (a) Make a table of rides for months 0 to 4 under each plan, rounding Plan 2 to whole rides. (b) Show that Plan 1 has equal differences and Plan 2 has equal factors. (c) Write a function for each plan.
Rubric
Criterion
Full Credit (2 pts)
Partial Credit (1 pt)
No Credit (0 pts)
Proofs
Works from an arbitrary interval x to x + h and simplifies correctly
Correct idea shown only with specific numbers
No proof or incorrect algebra
Tables
Differences or ratios computed and adjusted for interval length
Correct classification with incomplete evidence
Incorrect classification
Situations
Deciding words quoted, rate or percent rate named, function correct
Correct type with an error in the function
Incorrect type
Accuracy
All values correct and rounded sensibly
One or two arithmetic errors
Several errors
05
Quiz: 20 Questions
Interactive, with answers
Instructions
Answer each question, then open the explanation to check your reasoning. Your score updates as you go, and Reset quiz clears every answer so the quiz can be used again.
Multiple choice: pick an option to check it. Short answer: write your answer, then reveal the model answer.
0 of 20 answered · 0 correct
Question 1 of 20 · Multiple Choice
Which situation is best modeled by a linear function?
Answer: B
The pool gains the same amount, 35 gallons, in every minute: a constant rate per unit interval, so it is linear. Choices A, C and D each multiply the quantity by the same factor over equal intervals (1.03, 2 and 1/2), which makes them exponential. Choosing C because "doubles" sounds steady confuses a constant factor with a constant amount.
Question 2 of 20 · Multiple Choice
Which situation shows exponential decay?
Answer: A
Losing 20% each year leaves 80% of the value, so the value is multiplied by 0.8 each year: a constant percent rate of decay. Choice B is a decrease, but by a constant amount, so it is linear. Choice D is exponential growth, not decay.
Question 3 of 20 · Multiple Choice
A table shows x = 0, 1, 2, 3 and y = 5, 15, 45, 135. Which description fits?
Answer: D
The ratios are 15/5 = 45/15 = 135/45 = 3, so each unit multiplies y by 3: exponential. The differences are 10, 30 and 90, so choice A only looks at the first difference. Choice C uses the first difference, 10, as if it were a factor.
Question 4 of 20 · Multiple Choice
A table shows x = 0, 1, 2, 3 and y = 20, 14, 8, 2. Which description fits?
Answer: A
Each difference is 14 - 20 = 8 - 14 = 2 - 8 = -6, so the function is linear with a constant rate of -6 per unit. Choice B uses only the first ratio, 14/20 = 0.7; the next ratio is 8/14, about 0.57, so the factors are not equal. Choice C drops the sign of the change.
Question 5 of 20 · Multiple Choice
For f(x) = 6x - 1, what is f(x + 5) - f(x) for every x?
Answer: C
f(x + 5) - f(x) = 6(x + 5) - 1 - (6x - 1) = 30. The difference over an interval of length 5 is the slope times 5. Choice B is the change over an interval of length 1. Choice D subtracts the -1 once too often.
Question 6 of 20 · Multiple Choice
For g(x) = 3 · 4x, what is g(x + 2) ÷ g(x) for every x?
Answer: B
g(x + 2) ÷ g(x) = 3 · 4x + 2 ÷ (3 · 4x) = 42 = 16. Choice A multiplies the base by the interval length (4 · 2) instead of raising it to that power. Choice D keeps the coefficient 3, which cancels in the ratio.
Question 7 of 20 · Multiple Choice
A quantity grows at a constant percent rate of 6% per year. Each year, the quantity is multiplied by:
Answer: C
After a year the quantity is 100% + 6% = 106% of what it was, a factor of 1.06. Choice A would shrink the quantity to 6% of its size. Choice D is the factor for a 6% decrease.
Question 8 of 20 · Multiple Choice
A quantity decreases by 35% each week. What is its weekly growth factor?
Answer: D
Losing 35% leaves 100% - 35% = 65%, so the weekly factor is 0.65. Choice A is the percent lost, not the part that remains. Choice B is the factor for a 35% increase.
Question 9 of 20 · Multiple Choice
Which table shows an exponential function? Each table uses x = 0, 1, 2, 3.
Answer: C
In choice C every ratio is 1/2, so y is multiplied by the same factor over each unit: exponential decay. Choices B and D have equal differences (3 and 2), so they are linear. Choice A has differences 3, 5, 7 and ratios 4, 2.25, about 1.78, so it is neither; it is the squares (x + 1)².
Question 10 of 20 · Multiple Choice
Which statement about h(x) = 2x + 3 is true?
Answer: A
h(x + 1) - h(x) = 2(x + 1) + 3 - (2x + 3) = 2 for every x, so h grows by equal differences of 2. Choice B confuses the slope with a factor: h(0) = 3 and h(1) = 5, and 5/3 is not 2. Choice C takes the y-intercept as the rate.
Question 11 of 20 · Multiple Choice
A table shows x = 0, 1, 3, 6 and y = 4, 8, 32, 256. What model fits, and what is the factor per unit?
Answer: B
The intervals have lengths 1, 2 and 3. The ratios are 8/4 = 2 over 1 unit, 32/8 = 4 = 2² over 2 units and 256/32 = 8 = 2³ over 3 units, so the factor is 2 per unit: y = 4 · 2x. Choices C and D take a ratio over a longer interval as the factor per unit.
Question 12 of 20 · Multiple Choice
A quantity starts at 500. Which additional fact shows that an exponential model fits, rather than a linear one?
Answer: D
A constant percent rate per year, 8%, means the quantity is multiplied by 1.08 each year, which is exponential growth. Choice C is a constant rate per year, which gives a linear model. Choices A and B are true of both kinds of increasing models.
Question 13 of 20 · Multiple Choice
Which of these is modeled by a linear function?
Answer: B
Simple interest is always 5% of the original $1,000, so exactly $50 is added each year: a constant rate, so linear. In choice A the interest is 5% of the current balance, which grows, so the balance is multiplied by 1.05 each year: exponential. Choices C and D are also constant percent rates.
Question 14 of 20 · Multiple Choice
To prove that f(x) = mx + b grows by equal differences over equal intervals, which expression should you simplify?
Answer: A
The difference over an arbitrary interval, f(x + h) - f(x), simplifies to mh, which does not depend on x: that proves the claim for every interval of length h. Choice B tests for equal factors, the exponential pattern. Choices C and D check specific intervals, which gives evidence but not a proof.
Question 15 of 20 · Short Answer
Let p(x) = 1.5x + 4. Show that p changes by the same amount on the interval from 2 to 6 and on the interval from 9 to 13, and explain why.
p(6) - p(2) = 13 - 7 = 6 and p(13) - p(9) = 23.5 - 17.5 = 6. Both differences are 6. The intervals have the same length, 4, and for any x, p(x + 4) - p(x) = 1.5 · 4 = 6, so every interval of length 4 gives the same difference.
Question 16 of 20 · Short Answer
Prove that q(x) = 250(0.9)x is multiplied by the same factor over every interval of length 2. What is the factor, and what percent of the quantity is lost over each 2-unit interval?
q(x + 2) ÷ q(x) = 250(0.9)x + 2 ÷ (250(0.9)x) = 0.92 = 0.81. The x cancels, so the factor is 0.81 for every interval of length 2. The quantity keeps 81%, so it loses 19% over each 2-unit interval (not 20%).
Question 17 of 20 · Short Answer
A club's membership grew from 400 to 460 in the first year and from 460 to 529 in the second year. Is a linear or an exponential model a better fit? Explain.
The differences are 60 and 69, so they are not equal. The ratios are 460/400 = 1.15 and 529/460 = 1.15, so they are equal. Exponential: membership grows by a constant percent rate of 15% per year, M = 400(1.15)t.
Question 18 of 20 · Short Answer
Two coffee shops charge $3.00 for a coffee now. Shop 1 raises its price by 10 cents each year. Shop 2 raises its price by 4% each year. Which price is linear and which is exponential? Write a function for each.
Shop 1 adds the same amount each year, a constant rate: linear, C = 3 + 0.10t. Shop 2 multiplies its price by 1.04 each year, a constant percent rate: exponential, D = 3(1.04)t. After 1 year both are close ($3.10 and $3.12), but they grow in different ways.
Question 19 of 20 · Short Answer
A table shows x = 0, 1, 2, 3, 4 and y = 1000, 900, 810, 729, 656.1. Describe the change as a percent rate and write a function.
Each ratio is 900/1000 = 810/900 = 729/810 = 656.1/729 = 0.9, so y is multiplied by 0.9 each unit. Exponential decay at 10% per unit: y = 1000(0.9)x. The differences (-100, -90, -81, -72.9) are not equal, so it is not linear.
Question 20 of 20 · Short Answer
Quantity M starts at 50 and increases by 6 over every 2-unit interval. Quantity N starts at 50 and is multiplied by 1.2 over every 2-unit interval. Find each quantity at x = 2, 4 and 6, and name each model type.
M: 56, 62, 68. It adds the same amount over equal intervals, so it is linear (M = 50 + 3x). N: 60, 72, 86.4. It is multiplied by the same factor over equal intervals, so it is exponential. N adds 10, then 12, then 14.4.
0 of 20 answered · 0 correct
06
Frequently Asked Questions
10 Questions
What does HSF.LE.A.1 mean?
HSF.LE.A.1 means students can tell whether a situation is linear or exponential and can justify the choice. Part a asks them to prove that linear functions change by equal differences and exponential functions by equal factors over equal intervals. Parts b and c ask them to recognize those patterns in words: a constant rate per unit (linear) or a constant percent rate per unit (exponential).
Is HSF.LE.A.1 taught in Algebra 1 or Algebra 2?
It is usually taught in Algebra I, when exponential functions are first introduced next to linear ones. Algebra II returns to the same ideas with continuous growth, logarithms and more complex models, so students who master the difference-versus-factor test here use it again later.
How can you tell from a table if a function is linear or exponential?
Check the differences and the ratios of outputs over equal input intervals. If the differences are all equal, the function is linear. If the ratios are all equal, it is exponential. If neither is constant, the data are neither, for example a quadratic pattern such as 3, 4, 7, 12, 19.
What if the x-values in the table are not evenly spaced?
Then compare changes per unit, not raw changes. For a linear function, divide each difference by the length of its interval. For an exponential function, the ratio over an interval of length h should equal bh, so a ratio of 9 over 2 units means a factor of 3 per unit. A common mistake is to compare raw differences across intervals of different lengths.
What does it mean to "prove" that linear functions grow by equal differences?
It means showing the result for every interval of a given length, not just for the rows of a table. Start with f(x) = mx + b and an arbitrary interval from x to x + h. Then f(x + h) - f(x) = mh, and because x has cancelled, every interval of length h has the same difference. The exponential proof divides instead: a · bx + h ÷ (a · bx) = bh.
What is the difference between a constant rate and a constant percent rate?
A constant rate adds or subtracts the same amount each unit, such as 12 gallons per minute; that gives a linear function. A constant percent rate changes the quantity by the same percent of its current value each unit, such as 2.5% per year; that multiplies by the same factor (1.025) each unit and gives an exponential function.
Why is simple interest linear but compound interest exponential?
Simple interest is always a percent of the original deposit, so the same dollar amount is added each year. Compound interest is a percent of the current balance, which keeps growing, so the balance is multiplied by the same factor each year. For $2,000 at 3%, simple interest adds $60 every year, while compound interest adds $60, then $61.80, then about $63.65.
Is "drops 8 percentage points per hour" exponential?
No, it is linear. Percentage points of a fixed whole, such as a phone battery's full charge, are a constant amount: the battery goes 100%, 92%, 84% and so on. It would be exponential only if the battery lost 8% of its remaining charge each hour. Wording like this is worth practicing because students often react to the % sign alone.
What are common mistakes with HSF.LE.A.1?
Common mistakes include calling anything that grows quickly exponential, using the percent itself as the factor (0.04 instead of 1.04, or 0.25 instead of 0.75 for a 25% decrease), comparing changes over intervals of different lengths, and treating a few checked rows as a proof. Asking "subtract or divide?" for every table addresses most of them.
How does this standard connect to later topics?
It is the starting point for the rest of the cluster: students next construct linear and exponential functions from graphs, descriptions and tables (HSF.LE.A.2), compare their long-run growth (HSF.LE.A.3) and interpret their parameters in context (HSF.LE.B.5). On the digital SAT, linear models belong to the Algebra domain and exponential models to Advanced Math.
07
Related Standards
6 standards
These standards connect to HSF.LE.A.1: prerequisites to review first, parallel standards at the same level, and next steps that build on it.
Before this lesson
8.F.A.3Prerequisite
Interpret y = mx + b as a linear function and give examples of nonlinear functions